Given an integer n, generate a square matrix filled with elements from 1 to n2 in spiral order.
For example,
Given n =3,
[
[ 1, 2, 3 ],
[ 8, 9, 4 ],
[ 7, 6, 5 ]
]
https://oj.leetcode.com/problems/spiral-matrix-ii/
思路:按要求输出,注意边界。
public class Solution {
public int[][] generateMatrix(int n) {
int[][] mat = new int[n][n];
if (n <= 0)
return mat;
int num = 1;
int left = 0;
int right = n - 1;
int top = 0;
int bottom = n - 1;
while (num <= n * n) {
int i;
for (i = left; i <= right; i++)
mat[top][i] = num++;
for (i = top + 1; i <= bottom; i++)
mat[i][right] = num++;
if (top < bottom)
for (i = right - 1; i >= left; i--)
mat[bottom][i] = num++;
if (left < right)
for (i = bottom - 1; i >= top + 1; i--)
mat[i][left] = num++;
top++;
left++;
bottom--;
right--;
}
return mat;
}
public static void main(String[] args) {
System.out.println(new Solution().generateMatrix(1));
}
}
来源:oschina
链接:https://my.oschina.net/u/1584603/blog/284502