Pass only the arguments I want in a function

问题

Suppose I have a function like that:

public void Set(int a, string b, char c, float d, int e, float f, string g){
    //do something with a
    //do something with b
    //...
    //do something with g
}

I need to do only some of these things, based on the arguments I want to send to the function. The rest should be ignored.

For example: Set(a: 1, c: 'x', f: 1.4f, g: "hello"). Only the arguments I sent must be taken in account, the rest should just be ignored. How can I write such function that behaves like this?

Right now I'm passing a Dictionary<string, object> to the function and asking "Do you contain this key? If you do, execute something with its value", but I'd like to know if it's possible this way I'm asking, as it looks cleaner.

回答1:

Perhaps you can use a Dictionary<string, dynamic> : thus you can check the keys to have typed arguments.

public void Set(Dictionary<string, dynamic> data)
{
  if ( data.ContainsKey("a") )
    Console.WriteLine(data["a"]);
}

You can also use nullable parameters and if null you don't manage them:

public void Set(int? a, string b, char? c, float? d, int? e, float? f, string g)
{
  if ( a.HasValue ) Console.WriteLine(a); // also a.Value
}

I prefer this last that is more clean and robust.

With optional parameters:

public void Set(int? a = null, string b = null, char? c = null, float? d = null, int? e = null, float? f = null, string g = null)
{
}

Set(e: 10);

来源：https://stackoverflow.com/questions/65162175/pass-only-the-arguments-i-want-in-a-function

标签

function

arguments