问题
Well, I have this code:
http://jsfiddle.net/hv9gB/3/
(function() {
var img = document.getElementById('my_image');
// Original
var width, height;
// Display
var d_width = img.width;
var d_height = img.height;
var updateDetail = function() {
document
.getElementById('display_size')
.innerHTML = 'Display Size: ' + d_width + ' x ' + d_height;
document
.getElementById('native_size')
.innerHTML = 'Original Size: ' + width + ' x ' + height;
};
// Using naturalWidth/Height
if (img.naturalWidth) {
width = img.naturalWidth;
height = img.naturalHeight;
updateDetail();
} else {
// Using an Image Object
img = new Image();
img.onload = function() {
width = this.width;
height = this.height;
updateDetail();
};
img.src = 'http://lorempixel.com/output/nature-q-c-640-480-3.jpg';
}
}());
And that is my site:
http://dhems.x10.mx/
But on my site isn't working show the width and height of image
Why?!?!
回答1:
Put your code in
window.onload = function() {
//insert code here
}
Your js file is executed before the engine reach the picture..You're getting the following console error:
Uncaught TypeError: Cannot read property 'width' of null
It's also a good practice to put all scripts files in the end of the page and all css files in the begin. It will increase the loading time of your page, because if JS files are in the begin, your browser won't start to render until these files are downloaded.
your code should look like:
window.onload = function() {
var img = document.getElementById('my_image');
// Original
var width, height;
// Display
var d_width = img.width;
var d_height = img.height;
var updateDetail = function() {
document
.getElementById('display_size')
.innerHTML = 'Display Size: ' + d_width + ' x ' + d_height;
document
.getElementById('native_size')
.innerHTML = 'Original Size: ' + width + ' x ' + height;
};
// Using naturalWidth/Height
if (img.naturalWidth) {
width = img.naturalWidth;
height = img.naturalHeight;
updateDetail();
} else {
// Using an Image Object
img = new Image();
img.onload = function() {
width = this.width;
height = this.height;
updateDetail();
};
img.src = 'http://lorempixel.com/output/nature-q-c-640-480-3.jpg';
}
}
回答2:
Move the script tag after the image in HTML. Script gets executed before the image goes into page.
回答3:
Put the code at the bottom of your <body>
in a <script type='text/javascript'>
or use window.onload
. If you have other things loading onload
the first option is your best choice, otherwise use this code:
<script type='text/javascript'>
(function(){
var pre = window.onload;
onload = function(){
if(pre)pre();
//other code here
}
})();
</script>
This example can be used in your <head>
.
回答4:
<!DOCTYPE html>
<html>
<head>
<script src="http://ajax.googleapis.com/ajax/libs/jquery/2.0.2/jquery.min.js"></script>
<script>
function readImage(file) {
var reader = new FileReader();
var image = new Image();
reader.readAsDataURL(file);
reader.onload = function(_file) {
image.src = _file.target.result; // url.createObjectURL(file);
image.onload = function() {
var w = this.width,
h = this.height,
t = file.type, // ext only: // file.type.split('/')[1],
n = file.name,
s = ~~(file.size/1024) +'KB';
$('#uploadPreview').append('<img src="'+ this.src +'"> '+w+'x'+h+' '+s+' '+t+' '+n+'<br>');
};
image.onerror= function() {
alert('Invalid file type: '+ file.type);
};
};
}
$("#choose").change(function (e) {
if(this.disabled) return alert('File upload not supported!');
var F = this.files;
if(F && F[0]) for(var i=0; i<F.length; i++) readImage( F[i] );
});
</script>
<meta charset=utf-8 />
<title>Multiple image upload with preview by Roko C.B.</title>
</head>
<body>
<input type="file" id="choose" multiple="multiple" />
<br>
<div id="uploadPreview"></div>
</body>
</html>
来源:https://stackoverflow.com/questions/17255883/get-image-width-height-javascript