PHP - Getting a float variable internal value

问题

I am trying to establish the delta I need when doing float comparison in PHP. I want to take a closer look at my variables to see the difference.

I have 2 computed variables, $a, $b.

$a = some_function();

$b = some_other_function();

How can I see the exact number which PHP uses?

I want to compare them with this formula, where I need to specify the delta:

$delta = 0.00001;
if (abs($a-$b) < $delta) {
  echo "identical";
}

var_dump($a, $b) returns 1.6215; 1.6215. but I know that they are not exactly equal because

var_dump($a === $b);

evaluates to false;

Why doesn't var_dump() print the internal value?

回答1:

In PHP, the printed values of floating point numbers are dependent on PHP configuration "precision".

You can change that with:

ini_set('precision', YOUR_DESIRED_PRECISION_AS_INTEGER);

For example with with:

ini_set('precision', 18);

Your numbers may display something like:

float 1.62149999999999994

float 1.6214999999999995

So now the difference between them is clearer.

So your delta may be: $delta = 0.00000000000001; It really depends of the precision you are looking for.

If you need to do exact mathematical calculations, do have a look at the BC Math Functions.

References / Sources

PHP - Floating point numbers

PHP - Floating point numbers - User Contributed Notes - deminy at deminy dot net

Codepad

回答2:

If you don't want to edit your configuration file... you could use the round(val, precision) in your some_function() and some_other_function(). That way you can return the results to the precision you want. Check:
http://php.net/manual/en/function.round.php

来源：https://stackoverflow.com/questions/13800456/php-getting-a-float-variable-internal-value

标签

php

floating-point-precision