Hibernate exception. QuerySyntaxException: unexpected token: HAVING

问题

I try use this HQL query:

   Result.find("SELECT c, ( 3959 * acos( cos( radians(?) ) * "+
    "cos( radians( c.latitude ) ) *"+
    "cos( radians( c.longitude ) - radians(?) ) +"+
    "sin( radians(?) ) * sin( radians( c.latitude ) ) ) ) " +
    "AS distance FROM City c HAVING distance < ? ORDER BY distance ASC",
    latitude, longitude, latitude, radius).fetch();

But in result:

IllegalArgumentException occured : org.hibernate.hql.ast.QuerySyntaxException: unexpected token: HAVING near line 1, column 204 [SELECT c, ( 3959 * acos( cos( radians(?) ) * cos( radians( c.latitude ) ) *cos( radians( c.longitude ) - radians(?) ) +sin( radians(?) ) * sin( radians( c.latitude ) ) ) ) AS distance FROM models.City c HAVING distance < ? ORDER BY distance ASC]

回答1:

try changing HAVING to WHERE, in your query.

回答2:

The keyword HAVING is only allowed if you use GROUP BY (think of having like WHERE for GROUPS). See the reference manual for SELECT syntax.

回答3:

The only way is to use a native query because :

subselect is not possible : "Note that HQL subqueries can occur only in the select or where clauses." http://docs.jboss.org/hibernate/core/4.3/manual/en-US/html_single/#queryhql-subqueries
having is not possible without a group by
where is not possible neither

Java code :

@Query(value = "SELECT s.*,\n" +
            "  (\n" +
            "    3959 * acos(\n" +
            "        cos(radians(s.lat))\n" +
            "        * cos(radians(:lat))\n" +
            "        * cos(radians(:lon) - radians(s.lon))\n" +
            "        + sin(radians(s.lat))\n" +
            "          * sin(radians(:lat))\n" +
            "    )\n" +
            "  ) AS distance\n" +
            "FROM Stop s\n" +
            "HAVING distance < 30\n" +
            "ORDER BY distance asc", nativeQuery = true)
    List<Stop> findClosestStops(@Param("lat") Double lat, @Param("lon") Double lon);

An alternative is to return a list of object containg the city + distance, but no where is possible, but you can limit the resultset

回答4:

Hm, what should be "?" parameter?

If true you should use it like

HAVING distance < :distance

and use

query.setParameter("distance", 50);

回答5:

try

 select dis.c,dis.distance(
    SELECT c,
     ( 3959 * acos( cos( radians(?) ) *  cos( radians( c.latitude ) ) * 
cos( radians( c.longitude ) - radians(?) ) + sin( radians(?) ) *
 sin( radians( c.latitude ) ) ) )  AS distance FROM City c  ) dis 
where dis.distance<? order by dis.distance ASC

来源：https://stackoverflow.com/questions/10118449/hibernate-exception-querysyntaxexception-unexpected-token-having

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java

hibernate

hql