shellcode buffer overflow -SegFault

问题

I'm trying to run this shellcode but I keep getting segmentation fault

/* call_shellcode.c */
/*A program that creates a file containing code for launching shell*/
#include <stdlib.h>
#include <stdio.h>
#include <string.h>
const char code[] =
   "\x31\xc0" /* Line 1: xorl %eax,%eax */
   "\x50" /* Line 2: pushl %eax */
   "\x68""//sh" /* Line 3: pushl $0x68732f2f */
   "\x68""/bin" /* Line 4: pushl $0x6e69622f */
   "\x89\xe3" /* Line 5: movl %esp,%ebx */
   "\x50" /* Line 6: pushl %eax */
   "\x53" /* Line 7: pushl %ebx */
   "\x89\xe1" /* Line 8: movl %esp,%ecx */
   "\x99" /* Line 9: cdq */
   "\xb0\x0b" /* Line 10: movb $0x0b,%al */
   "\xcd\x80" /* Line 11: int $0x80 */
   ;
int main(int argc, char **argv)
{
   char buf[sizeof(code)];
   strcpy(buf, code);
   ((void(*)( ))buf)( );
}

I compile it using:

 gcc -z execstack -o call_shellcode call_shellcode.c

and

 gcc -fno-stack-protector -z execstack -o call_shellcode call_shellcode.c

But I keep getting segmentation fault

Also, I'm running a 64 bit Linux system (ubuntu)

回答1:

You are using a 32 bit assembly code on a x86-64 system. So, It is your problem, you have to create your shellcode for x86-64 systems.

E.g.

  400078:   48 31 c0                xor    rax,rax
  40007b:   48 bf 2f 2f 62 69 6e    movabs rdi,0x68732f6e69622f2f
  400082:   2f 73 68 
  400085:   48 31 f6                xor    rsi,rsi
  400088:   56                      push   rsi
  400089:   57                      push   rdi
  40008a:   48 89 e7                mov    rdi,rsp
  40008d:   48 31 d2                xor    rdx,rdx
  400090:   b0 3b                   mov    al,0x3b
  400092:   0f 05                   syscall

One of the main differences with 32 bits assembly, is how to use the syscalls. In this link Linux Syscalls x86-64 you can see what registers you need to call the sys_execve

int execve(const char *filename, char *const argv[], char *const envp[]);

const char *filename -> rdi
char *const argv[] -> rsi
char *const envp[] -> rdx

E.g.

  #include <stdlib.h>
  #include <stdio.h>
  #include <string.h>

  const char code[] = "\x48\x31\xc0\x48\xbf\x2f\x2f\x62\x69\x6e\x2f\x73\x68\x48\x31\xf6\x56\x57\x48\x89\xe7\x48\x31\xd2\xb0\x3b\x0f\x05";
  int main(int argc, char **argv)
  {
       char buf[sizeof(code)];
       strcpy(buf, code);
       ((void(*)( ))buf)( );
  }

Compilation and test it.

$ gcc -fno-stack-protector -z execstack shellcode.c -o shellcode
$ ./shellcode 
$ uname -a
 Linux foobar 4.4.0-97-generic #120-Ubuntu SMP Tue Sep 19 17:28:18 UTC 2017 x86_64 x86_64 x86_64 GNU/Linux

回答2:

code doesn't have a trailing null byte, so you can't use strcpy() to copy it. Use memcpy().

memcpy(buf, code, sizeof(code));

As mentioned in a comment, the shellcode you have is for 32-bit Linux, but you're trying to run it on a 64-bit system. That probably explains the error after fixing this.

来源：https://stackoverflow.com/questions/47144272/shellcode-buffer-overflow-segfault

标签

gcc

segmentation-fault

buffer-overflow

shellcode