问题
Let's say we have this folders
not_my_files
collections
collection1.xml
collection2.xml
collection3.xml
etc...
my_files
my_documents
mydoc1.xml
mydoc2.xml
mydoc3.xml
etc...
There are the structure of xml files
collection1.xml (same structure for collection2.xml, collection3.xml, etc...)
<collection xml:id="name_of_collection_1">
<ref id="id_of_ref_1">
<title>This is title 1 of first document in this collection</title>
</ref>
<ref id="id_of_ref_2">
<title>This is title 2 of second document in this collection</title>
</ref>
</collection>
mydoc1.xml (same structure for mydoc2.xml, mydoc3.xml, etc...)
<mydoc id="my_doc_id_1">
<tag1>
<tag2>
<reference_tag>
<my_title>This is title 1 of my documents</my_title>
</reference_tag>
</tag2>
</tag1>
</mydoc>
So: 1) xml files in different folders have different structure and 2) collection1.xml can contain many titles and mydoc1.xml can contain only 1 title in time.
I want to get all titles from both collections/collection1.xml (etc.) AND my_documents/mydoc1.xml (etc.). This is a desired result:
<doc>
<folder>Not my files</folder>
<title>This is title 1 of first document in this collection</title>
</doc>
<doc>
<folder>Not my files</folder>
<title>This is title 2 of second document in this collection</title>
</doc>
<doc>
<folder>My files</folder>
<title>This is title 1 of my documents</title>
</doc>
My current XQuery:
xquery version "3.1";
for $doc_not_my_files in collection("/not_my_files/collections")
let $folder_not_my_files := "Not my files"
for $ref in $doc_not_my_files//ref
let $title_not_my_files := $ref/title/text()
for $doc_my_files in collection("/my_files/my_documents")
let $folder_my_files := "My files"
let $title_my_files := $doc_my_files//reference_tag/my_title/text()
return
if ($folder_my_files="My files")
then
<doc>
<folder>{$folder_my_files}</folder>
<title>{$title_my_files}</title>
</doc>
else
<doc>
<folder>{$folder_not_my_files}</folder>
<title>{$title_not_my_files}</title>
</doc>
My current result:
<doc>
<folder>My files</folder>
<title>This is title 1 of my documents</title>
</doc>
<doc>
<folder>My files</folder>
<title>This is title 1 of my documents</title>
</doc>
<doc>
<folder>My files</folder>
<title>This is title 1 of my documents</title>
</doc>
<doc>
<folder>My files</folder>
<title>This is title 1 of my documents</title>
</doc>
**etc... 1000 times**
<doc>
<folder>Not my files</folder>
<title>This is title 1 of first document in this collection</title>
</doc>
<doc>
<folder>Not my files</folder>
<title>This is title 1 of first document in this collection</title>
</doc>
<doc>
<folder>Not my files</folder>
<title>This is title 1 of first document in this collection</title>
</doc>
**etc... another 1000 times**
So, I looking for some kind of SQL "UNION" alternative in XQuery... I have this feeling like I have some basic stupid question, but I'm new to XQuery, so forgive me:)
回答1:
It might work with
for-each-pair(
collection("/my_files/my_documents"),
collection("/not_my_files/collections"),
function($doc, $col) {
$doc//reference_tag/my_title/text() ! <doc>
<folder>My files</folder>
<title>{.}</title>
</doc>,
$col//ref/title/text() ! <doc>
<folder>Not my files</folder>
<title>{.}</title>
</doc>
}
)
来源:https://stackoverflow.com/questions/64467039/combine-two-for-loops-and-union-results-in-xquery