How to build inverse relationship to Entity which has more than two relationship to it?

流过昼夜 提交于 2021-02-08 08:04:37

问题


I have an entities Group and Person with relationships:

Group:

Group.leader ->  Person (To One)
Group.looser ->  Person (To One)
Group.others ->> Person (To Many)

In leader, looser and others set I could have different Person entities. Same Person could be leader in one group, looser in second and appears in others set in third group.

in Person entity I have To-Many relationship groups which should connect

Person:

Person.groups ->> Group (should be enough but warnings)

Because I can make only one inverse relationship I always will have a warning "something should have inverse"

How to deal with relationships like this?

Or: I have entities Cube, Plan and Line. Cube has relationships x, y, z, Plane x and y, Line just x. And I need to share some values between them, even sometimes mixed:

Cube:
Cube.x --> Value
Cube.y --> Value
Cube.z --> Value

Plane:
Cube.x --> Value
Cube.y --> Value

Line:
Cube.x --> Value

Value:
Value.counted -->> Line.x or Line.y, Plane.x, Cube.x, y, z, SomeAnotherEntity.neededValue

回答1:


Apple recommend that every relationship should have an inverse. In your case, that would mean the Person entity would have three relationships:

Person.groupsLed ->> Group (to many) // "groups where this Person is leader"
Person.groupsLost ->> Group (to many) // "groups where this person is the looser"
Person.otherGroups ->> Group (to many) // "other groups with this person as a member"

which does seem rather complicated. One alternative would be to collapse the three relationships into one (for each of Person and Group) with an intermediate entity (Ranking?):

Group.rankings ->> Ranking (to many) // "the ranking of people for this group"
Person.rankings ->> Ranking (to many) // "the ranking of this person in different groups"

In each case the inverse would be to-one:

Ranking.person -> (Person) (to one) // "the person for this ranking"
Ranking.group -> (Group) (to one) // "the group for this ranking"

You can then add an attribute to the Ranking entity to indicate the leaders/loosers/other. That could be a simple string attribute rank which takes the values "leader", "looser" or "other", or an equivalent integer enum. To manage the relationship between a Group and a Person, you add or remove Ranking objects. One downside to all this is that finding the leader or looser involves filtering the rankings, but it does give you a degree of flexibility.



来源:https://stackoverflow.com/questions/46686694/how-to-build-inverse-relationship-to-entity-which-has-more-than-two-relationship

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