问题
I have a stream function KStream<K, V>[] branch(final Predicate<? super K, ? super V>... predicates)
. I wanted to create a list of predicates dynamically. Is that possible?
KStream<Long, AccountMigrationEvent>[] branches = stream
.map((key, event) -> enrich(key, event))
.branch(getStrategies());
[...]
private List<org.apache.kafka.streams.kstream.Predicate<Long, AccountMigrationEvent>> getStrategies() {
ArrayList<Predicate<Long, AccountMigrationEvent>> predicates = new ArrayList<>();
for (MigrationStrategy strategy : strategies) {
predicates.add(new org.apache.kafka.streams.kstream.Predicate<Long, AccountMigrationEvent>() {
@Override
public boolean test(Long key, AccountMigrationEvent value) {
return strategy.match(value);
}
});
}
return predicates;
}
回答1:
I haven't tested this code but in theory it should work:
//All the predicates mentioned in here are of type org.apache.kafka.streams.kstream.Predicate
private Predicate<Long, AccountMigrationEvent>>[] getStrategies() {
List<Predicate<Long, AccountMigrationEvent>> predicates = strategies.stream()
.map(strategy -> (Predicate<Long, AccountMigrationEvent>>) (key, value) -> strategy.matches(value))
.collect(toList());
// branch() method on KStream requires an array so we need to transform our list
return predicates.toArray(new Predicate[predicates.size()]);
}
来源:https://stackoverflow.com/questions/55902587/collection-of-lambda-functions-in-java-streams