Stack Overflow Error on recursion java

问题

I need to find the longest way (from bigger to lower) between numbers in array. I've tried to write recursive function and got java.lang.StackOverflowError, but for the lack of knowledge I didn't understand why this happened.

Firstly, I've initialize array and fill it with random numbers:

public long[] singleMap = new long[20];
for (int i = 0; i < 20; i++) {
        singleMap[i] = (short) random.nextInt(30);
    }

Then, I try to find the longest route of counting down numbers (e.g. { 1, 4, 6, 20, 19, 16, 10, 6, 4, 7, 6, 1 ...} ) and to return the count such numbers.

 public int find(long[] route, int start) {
    if (route[start] > route[start + 1]) {
        find(route, start++);
    } else {
        return start;
    }
    return start;
}

So here's log:

 08-23 13:06:40.399 4627-4627/itea.com.testnotification I/dalvikvm:   threadid=1: stack overflow on call to    Litea/com/testnotification/MainActivity;.find:ILI
 08-23 13:06:40.399 4627-4627/itea.com.testnotification I/dalvikvm:   method requires 36+20+12=68 bytes, fp is 0x4189e318 (24 left)
 08-23 13:06:40.399 4627-4627/itea.com.testnotification I/dalvikvm:   expanding stack end (0x4189e300 to 0x4189e000)
 08-23 13:06:40.400 4627-4627/itea.com.testnotification I/dalvikvm: Shrank stack (to 0x4189e300, curFrame is 0x418a3e88)
 08-23 13:06:40.400 4627-4627/itea.com.testnotification D/AndroidRuntime: Shutting down VM
 08-23 13:06:40.400 4627-4627/itea.com.testnotification W/dalvikvm: threadid=1: thread exiting with uncaught exception (group=0x41a8ed40)
 08-23 13:06:40.414 4627-4627/itea.com.testnotification E/AndroidRuntime: FATAL EXCEPTION: main
                                                                         Process: itea.com.testnotification, PID: 4627
                                                                     java.lang.StackOverflowError
                                                                         at itea.com.testnotification.MainActivity.find(MainActivity.java:46)
                                                                         at itea.com.testnotification.MainActivity.find(MainActivity.java:46)

I appreciate any explanation because all related issues didn't help me. If there is a problem in my function, please correct or explain.

EDIT

I forgot to say, that I use for to check the longest way from each "point"

  for (int i = 0; i < singleMap.length - 1; i++) {
        int x = find(singleMap, i);
        System.out.println("steps = " + x);
    }

回答1:

You need to mantain the current max find up to now, and the current value. So change it as follow:

public int find(int[] route, int start, int max, int currentMax) {
    if (currentMax > max) {
        max = currentMax;
    }
    if (start == route.length - 1) {
        return max;
    }
    if (route[start] > route[start + 1]) {
        return find(route, start + 1, max, currentMax + 1);
    }
    return find(route, start + 1, max, 1);
}

And call it with a starting

find(route, 0, 1, 0);

A second alternative is to rewrite it without recursion:

public int find(int[] route) {
    int max = 1;
    int currentMax = 1;
    for (int i = 0; i < route.length - 1; i++) {
        if (route[i] > route[i + 1]) {
            currentMax++;    // If next element is lower increment currentMax
            if (currentMax > max) {
                max = currentMax;   // If currentMax is the new max update max
            }

        } else {
            currentMax = 1;   // If next element is not lower restart from 1
        }
    }
    return max;
}

and call it as

find(route);

回答2:

First of all change

find(route, start++)

find(route, start+1)

since post-increment returns the original value of the variable, so the recursion never advances, leading to StackOverflowError.

You should also add a stopping condition, otherwise your next exception would be ArrayIndexOutOfBoundsException.

As Kevin commented, you should also do something with the value returned by find(route, start++);. Otherwise there is no point in calling it at all.

Besides those issues, your logic is wrong. The method will return the last index of the descending sequence starting at the beginning of the array, which tells you nothing about the longest descending sequence. For example, for { 1, 4, 6, 20, 19, 16, 10, 6, 4, 7, 6, 1 ...} your method would return 0 (the first index of the array), since route[0] > route[1] is false.

回答3:

When you call start++ you perform a postincrementation. It means that the operation occurs after passing the parameter to the method - which means that your method just keeps going around in circles on the first parameter until the memory runs out. Replace it with start+1 and you'll get the whole new bunch of exceptions to have fun with ;)

回答4:

You have several problems in the algorithm that other users pointed here. But the main problem is that this algorithm must not be recursive. Recursively, you can only find the length of the descending sequence that starts at the zero index.

A correct algorithm must run through the whole array:

public static int find(long[] route) {
    int maxIdx = 0;
    int maxCount = 1;
    for (int i = 1, c = 0; i < route.length; i++) {
        if (route[i] < route[i - 1]) {
            if (++c >= maxCount) {
                maxCount = c;
                maxIdx = i - c;
            }
        } else {
            c = 0;
        }
    }
    return route.length == 0 ? -1 : maxIdx;
}

来源：https://stackoverflow.com/questions/39098680/stack-overflow-error-on-recursion-java

标签

java

recursion

stack-overflow