问题

I'm building a micro-service that has an Apache Camel route using Netty4 Component (http://camel.apache.org/netty4.html) in consumer mode. So, in my micro-service, this route that I'm building, will receive messages over a a TCP connection. To do that, I did this:

@Override
public void configure() throws Exception {
 this.from("netty4:tcp://localhost:7000?textline=true&encoding=utf8")
   .process(new Processor() {
      @Override
      public void process(final Exchange exchange) throws Exception {
        log.info("[Processor] - Incoming Message -> {}", exchange.getIn().getBody(String.class));
      }
   }).to("bean:messageService");
}

Well, I'm receiving the messages normally. To test, I use telnet:

$ telnet localhost 7000
Trying 127.0.0.1...
Connected to localhost.
Escape character is '^]'.
TheMessage

The problem is when I want to send back a message to the same TCP channel established in that route. In synchronous mode, I can do that easily using the Exchange object. However, in asynchronous mode, I don't know how to send back a message to the producer.

The Spring Service that receive and should send the messages, is this:

@Service
public class MessageService {

  private static final Logger log = LoggerFactory.getLogger(MessageService.class);

  private List<String> messageStore = new LinkedList<>();

  public void sendToTCP(final String message) {
    log.info("[Service] - Sending Message over TCP Channel --> {}", message);
  }

  @Handler
  public void receiveFromTCP(final Exchange exchange) {
    final String messageFromTcp = exchange.getIn().getBody(String.class);
    log.info("[Service] - Message Received from TCP Channel --> {}", messageFromTcp);
    this.messageStore.add(messageFromTcp);
  }

  public List<String> getReceivedMessages() {
    return messageStore;
  }
}

In resume, what I need is to put some code in this method, something like that:

public void sendToTCP(final String message) {
  log.info("[Service] - Sending Message over TCP Channel --> {}", message);
  // Send message to producer here
  camelContext.createProducerTemplate.send....
}

I cannot create another route to producer because I don't know the producer IP. I really need to use the already established TCP channel between the producer and my application. The communication needs to be over TCP, other tools, like Queues, are not an option.

GitHub Sample Project

I uploaded a sample project on GitHub: https://github.com/rgiaviti/so-camel-netty4-tcp

Draw

I'm using:

Spring Boot 1.5.12;
Apache Camel 2.21.0;

回答1:

Found a solution based on comment by @vikram-palakurthi.

I used the Netty4 property reuseChannel. The solution code is close to this:

  private static final Logger log = LoggerFactory.getLogger(MessageService.class);

  private List<String> messageStore = new LinkedList<>();
  private Channel openedChannel;

  public void sendToTCP(final String message) {
    log.info("[Service] - Sending Message over TCP Channel --> {}", message);
    log.info("[Service] - Channel is Active? {}", this.openedChannel.isActive());
    log.info("[Service] - Channel is Open? {}", this.openedChannel.isOpen());
    log.info("[Service] - Channel is Writeble? {}", this.openedChannel.isWritable());

    this.openedChannel.write(message);
    this.openedChannel.flush();
  }

  @Handler
  public void receiveFromTCP(final Exchange exchange) {
    this.openedChannel = exchange.getProperty(NettyConstants.NETTY_CHANNEL, Channel.class);
    final String messageFromTcp = exchange.getIn().getBody(String.class);
    log.info("[Service] - Message Received from TCP Channel --> {}", messageFromTcp);
    this.messageStore.add(messageFromTcp);
  }

Camel Solution

The complete solution with Camel Routes, Processor... can be found here: https://github.com/rgiaviti/so-camel-netty4-tcp/tree/solution

However, we need to know this is a simple solution. The developer still needs to handle with multiple channels, closing channels by producer, checking channels...