问题
I am grouping my dataset by column A and then would like to take the minimum value in column B and the corresponding value in column C.
data = pd.DataFrame({'A': [1, 2], 'B':[ 2, 4], 'C':[10, 4]})
data
A B C
0 1 4 3
1 1 5 4
2 1 2 10
3 2 7 2
4 2 4 4
5 2 6 6
and I would like to get :
A B C
0 1 2 10
1 2 4 4
For the moment I am grouping by A, and creating a value that indicates me the rows I will keep in my dataset:
a = data.groupby('A').min()
a['A'] = a.index
to_keep = [str(x[0]) + str(x[1]) for x in a[['A', 'B']].values]
data['id'] = data['A'].astype(str) + data['B'].astype('str')
data[data['id'].isin(to_keep)]
I am sure that there is a much more straight forward way to do this. I have seen many answers here that use multi-indexing but I would like to do this without adding multi-index to my dataframe. Thank you for your help.
回答1:
I feel like you're overthinking this. Just use groupby
and idxmin
:
df.loc[df.groupby('A').B.idxmin()]
A B C
2 1 2 10
4 2 4 4
df.loc[df.groupby('A').B.idxmin()].reset_index(drop=True)
A B C
0 1 2 10
1 2 4 4
回答2:
Had a similar situation but with a more complex column heading (e.g. "B val") in which case this is needed:
df.loc[df.groupby('A')['B val'].idxmin()]
来源:https://stackoverflow.com/questions/54470917/pandas-groupby-and-select-rows-with-the-minimum-value-in-a-specific-column