问题
I have a bunch of files in a directory all named YYYY_MM_DD
-rw-r--r-- 1 root root 480K Apr 21 13:17 2012_04_05
-rw-r--r-- 1 root root 483K Apr 21 13:17 2012_04_06
-rw-r--r-- 1 root root 484K Apr 21 13:17 2012_04_07
-rw-r--r-- 1 root root 480K Apr 21 13:17 2012_04_08
-rw-r--r-- 1 root root 344K Apr 21 13:17 2012_04_09
-rw-r--r-- 1 root root 66K Apr 21 13:17 2012_04_10
-rw-r--r-- 1 root root 461K Apr 21 13:17 2012_04_11
-rw-r--r-- 1 root root 475K Apr 21 15:09 2012_04_17
-rw-r--r-- 1 root root 480K Apr 21 15:10 2012_04_18
-rw-r--r-- 1 root root 474K Apr 21 15:10 2012_04_19
-rw-r--r-- 1 root root 474K Apr 21 15:10 2012_04_20
I have a shell script that accepts a file as a paramater and calculates figures based on the data in the file, i call the script like this
sh Calculate.sh MyFile
I want to run this shell script for every file in this directory.
How would i go about doing this, xargs ??
回答1:
Have you tried the find
command with execution ?
My sample will echo the files, but you can call a shell script with the filename as a parameter
find . -maxdepth 1 -type f -exec echo {} \;
回答2:
A simple for loop in the shell:
for file in *; do sh Calculate.sh "$file"; done
回答3:
find . -maxdepth 1 -type f | xargs -n 1 -I % Calculate.sh %
回答4:
./Calculate.sh 2012_04_{05..20}
来源:https://stackoverflow.com/questions/10259836/run-shell-script-for-every-file-in-directory