'find' using regex with variables

问题

Please, help me with the following:

Let it be three files:

file-aaa.sh 
file-bbb.sh
file-xxx.sh

In a bash script I have variables

$a=aaa 
$b=bbb

Now, I want to execute something like:

find . -name "file-[$a|$b].sh"

and expect to get two files in output. What am I doing wrong?

回答1:

You can use this find:

find . -name "file-$a.sh" -o -name "file-$b.sh"

To combine it into one using -regex option:

On OSX:

find -E . -regex ".*file-($a|$b)\.txt"

On Linux:

find . -regextype posix-extended -regex ".*file-($a|$b)\.txt"

来源：https://stackoverflow.com/questions/24552144/find-using-regex-with-variables