Open another Mac app | 易学教程

问题

In my app I would like to open another app that is installed on the User's Mac (such as iPhoto). I am not sure what I should be looking for in the documentation. What is this called and how should I do it? Thank you

回答1:

Xcode 8.3.2 • Swift 3.1

import Cocoa

func openPhotos() {
    NSWorkspace.shared().open(URL(fileURLWithPath: "/Applications/Photos.app"))
}

openPhotos()

Or using launchApplication with the app name parameter in the method:

import Cocoa

func openApp(_ named: String) -> Bool {
    return NSWorkspace.shared().launchApplication(named)
}

// Usage

if openApp("Photos") {
    print(true)
}

// Or

print(openApp("Photos") ? true : false)

Swift 4 and later

Use NSWorkspace.shared instead of NSWorkspace.shared()

回答2:

XCode 11 • MacOS Catalina 10.15 • Swift 5

NSWorkspace.shared.launchApplication is deprecated and starting from the MacOS 10.15 the new function NSWorkspace.shared.openApplication shall be used.

Example - open terminal application by its bundle id

guard let url = NSWorkspace.shared.urlForApplication(withBundleIdentifier: "com.apple.Terminal") else { return }

let path = "/bin"
let configuration = NSWorkspace.OpenConfiguration()
configuration.arguments = [path]
NSWorkspace.shared.openApplication(at: url,
                                   configuration: configuration,
                                   completionHandler: nil)

Example - open terminal application by its path

let url = NSURL(fileURLWithPath: "/System/Applications/Utilities/Terminal.app", isDirectory: true) as URL

let path = "/bin"
let configuration = NSWorkspace.OpenConfiguration()
configuration.arguments = [path]
NSWorkspace.shared.openApplication(at: url,
                                   configuration: configuration,
                                   completionHandler: nil)

回答3:

You can use NSWorkspace class written by Swift/Cocoa.

https://developer.apple.com/library/mac/documentation/Cocoa/Reference/ApplicationKit/Classes/NSWorkspace_Class/index.html#//apple_ref/occ/instm/NSWorkspace/launchApplication:

回答4:

let task = NSTask.launchedTaskWithLaunchPath(<#path: String#>, arguments: <#[AnyObject]#>) will probably do what you want

回答5:

There are different ways to do that. The most efficient is to use fvork and execve - see man vfork and man execve.

Less efficient but more flexible is to use the system library call. What that actually does is runs a shell - like bash - then passes the string you provide, to bash. So you can set up pipelines, redirection and such.

Or you can send an Apple Event to the Finder: "Tell Finder Open iPhoto".

In the first two cases you want to launch the executable inside the bundle, that is, /Applications/iPhoto.app/Contents/MacOS/iPhoto.

Try the above from the command line, in the Terminal:

$ /Applications/iPhoto.app/Contents/MacOS/iPhoto

You'll see the iPhoto App launch.

回答6:

I second the answer by vookimedlo - unfortunately, I cannot yet comment (silly reputation limit) so I post this as an extra answer.

This is just one caveat, which might not affect too many: while launchApplication() accepted a path to an executable (e.g. "MyApp.app/Contents/MacOS/MyApp"), this will result in an error (lacking privileges) with openApplication(::). You have to supply the path to the app bundle ("MyApp.app") instead.

Of particular interest when you try to make a helper ("launcher") to add as a login item. See the following and keep my comment in mind:

https://theswiftdev.com/2017/10/27/how-to-launch-a-macos-app-at-login/ (GREAT article by Tibor Bödecs)

BTW, as for vookimedlo's code: in my experience, you don't need to specify the OpenContext.arguments with [path], you can simply pass a default NSWorkspace.OpenContext()...

来源：https://stackoverflow.com/questions/27505022/open-another-mac-app

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