Change file's numbers Bash

问题

I need to implement a script (duplq.sh) that would rename all the text files existing in the current directory using the command line arguments. So if the command duplq.sh pic 0 3 was executed, it would do the following transformation:

pic0.txt will have to be renamed pic3.txt

pic1.txt to pic4.txt

pic2.txt to pic5.txt

pic3.txt to pic6.txt

etc…

So the first argument is always the name of a file the second and the third always a positive digit.

I also need to make sure that when I execute my script, the first renaming (pic0.txt to pic3.txt), does not erase the existing pic3.txt file in the current directory.

Here's what i did so far :

 #!/bin/bash

name="$1"
i="$2"
j="$3"


for file in $name*
do
    echo $file
    find /var/log -name 'name[$i]' | sed -e 's/$i/$j/g'
    i=$(($i+1))
    j=$(($j+1))
done

But the find command does not seem to work. Do you have other solutions ?

回答1:

A possible solution...

#!/bin/sh

NUMBERS=$(ls $1|sed -e 's/pic//g' -e 's/\.txt//g'|sort -n -r)

for N in $NUMBERS
do
    NEW=$(($N + 3))
    echo "pic$N.txt -> pic$NEW.txt"
    mv "pic$N.txt" "pic$NEW.txt"
done

回答2:

find possible files, sort the names by number, use sed to remove files with lower numbers than $1, reverse sort by number, and start at the top renaming from the highest number down to the lowest:

#!/bin/sh
find . -maxdepth 1 -type f -name "$1"'[0-9]*' | 
sort -g | sed -n "/^$1$2."'/,$p' | sort -gr | 
while read x ; do
    p="${x%%[0-9]*.*}"; s="${x##*[0-9]}" ; i="${x%$s}" i="${i#$p}"
    mv "$x" "$p$((i+$3))$s"
done

来源：https://stackoverflow.com/questions/49968718/change-files-numbers-bash

标签

Linux

bash

shell

rename