问题
I have a bit weird requirement where I need to generate Random numbers of the length that is given by user. User can give Minimum Length
and the Maximum Length
and I need to generate the random numbers which consist of the character length between this range.
For example if the Minimum Length
is 6
and Maximum Length
is 10
then I need to generate the random numbers whose number of characters has to be between the range 6
and 10
. For this example following can be the random generators:
123456,
7654321,
12345678,
987654321,
5432109876, etc.
Like this the Random generators has to contain the length which is between the provided inputs.
I know how to create random numbers between a range and based on fixed character length but I don't know how to created based on variable length. I tried finding the answers but most of them are based on the fixed length and fixed range, could not find the exact match that I am looking for.
It would be really great if someone can help me with this.
回答1:
You may produce an array (Array.from() of randomly chosen length in the range of minLen
and maxLen
) and populate that with random digits in the range 1 through 9, then Array.prototype.join() the array into string and convert to number:
const randomNum = (minLen, maxLen) =>
+Array
.from(
{length: 0|Math.random()*(maxLen-minLen+1)+minLen},
() => 0|Math.random()*9+1
)
.join('')
console.log(randomNum(3,7))
回答2:
You could generate the range and get the random values from that range.
For example
min = 2
max = 4
rangeMin = 10
rangeMax = 10000
const
getRandom = (min, max) => Math.floor(Math.random() * (max - min)) + min,
getRandomX = (min, max) => getRandom(10 ** (min - 1), 10 ** max);
let min = Infinity,
max = -Infinity;
for (let i = 0; i < 1e6; i++) {
let r = getRandomX(6, 10);
if (min > r) min = r;
if (max < r) max = r;
}
console.log(min, max);
.as-console-wrapper { max-height: 100% !important; top: 0; }
回答3:
Other solutions generate randoms for each digit and join them together to form a number. This is unnecessary. We know that a number with at least m
-th digits is at least 10m - 1. Similarly, having at most n
digits means that the number is smaller than 10n.
const randomWithinRange = (min, max) => Math.floor(Math.random() * (max - min) + min);
const randomWithMagnitude = (min, max) => randomWithinRange(Math.pow(10, min - 1), Math.pow(10, max));
const arr = Array(100000).fill().map(() => randomWithMagnitude(6, 10)).sort((a, b) => a - b);
console.log(arr.slice(0, 100).join(", "));
console.log(arr.slice(99900, 100000).join(", "));
Note: I've sorted the 100.000-sized array just to show you the smallest and largest numbers generated.
回答4:
Try this:
var minLength = 6;
var maxLength = 10;
var generatedNumbers = [];
for(var i=minLength ; i<=maxLength; i++){
var num = "";
for(var j=1;j<=i;j++){
num = num + Math.floor(Math.random(10) * 10);
}
generatedNumbers.push(num);
}
console.log(generatedNumbers);
Edit
var minLength = 1;
var maxLength = randomNumber;
var generatedNumbers = [];
for(var i=minLength ; i<=maxLength; i++){
var num = "";
for(var j=1;j<=i;j++){
num = num + Math.floor(Math.random(10) * 10);
}
generatedNumbers.push(num);
}
console.log(generatedNumbers);
this will help.
回答5:
Thanks a lot, everyone for the answer. Here is the approach that I have used.
If the random numbers with just Numeric is required:
var charset = "0123456789";
var max_Length = 5;
var min_Length = 10;
var charPicker = Math.floor(Math.random() * (max_Length - min_Length + 1) + min_Length);
var randomId;
for (var i = 0; i < charPicker; i++)
{
randomId += charset.charAt(Math.floor(Math.random() * charset.length));
}
console.log(randomId);
Change the character set for Alphanumeric and Alphanumeric with URL specific characters like this:
var charset = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789";
var charset = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789-._~()'!*:@,;";
来源:https://stackoverflow.com/questions/62468165/how-to-generate-random-numbers-in-javascript-based-on-the-provided-range-minimum