recvfrom with Raw Sockets, get just the data

问题

I'm trying to implement my own transport layer protocol, but I'm perfectly happy to leave the network layer as-is and not need to mess with the actual IP header information.

But of course, when calling recvfrom() on a raw socket, you are given the raw IP datagram, while the sockaddr struct is not filled in.

Is there anyway to coax the stack to fill in those structs and leave the ip header out of the data portion, or does that need to be implemented by hand?

Receiver:

struct sockaddr_in sender;
int sender_len;

raw_socket = socket(AF_INET, SOCK_RAW, 56);

...

if((n = recvfrom(raw_socket, buf, 1024, 0, (struct sockaddr*)&sender, &sender_len)) == -1){
    perror("recvfrom");
    return -1;
}

回答1:

The IP header will always be included when receiving on a SOCK_RAW socket.

Per raw(7):

The IPv4 layer generates an IP header when sending a packet unless the IP_HDRINCL socket option is enabled on the socket. When it is enabled, the packet must contain an IP header. For receiving the IP header is always included in the packet.

Reference:

• ip(7) man page
• SOCK_RAW Demystified
• Advanced TCP/IP - THE RAW SOCKET PROGRAM EXAMPLES

回答2:

Use recvmsg() with the msg[] buffers initialized so that the first one receives the IP header, then the second one will only contain data.

来源：https://stackoverflow.com/questions/26896944/recvfrom-with-raw-sockets-get-just-the-data