问题
I'm doing a .toString() on an InetSocketAddress. This is part of an Android websocket client that so far is failing to connect to the host.
Right now the output from a variable address.toString() looks like domain.com/72.xx.xxx.xx:8000 but from what I understand there needs to be two values (IP and port) only?
Thanks letting me know if this looks correct.
回答1:
The toString() of InetSocketAddress first calls the toString() of InetAddress and then appends the port number to it and the string returned from toString() of InetAddress is of the form: hostname / literal IP address.
Later port number is concatenated before returning from the InetSocketAddress's toString() to the returned value (from the toString() of InetAddress), hence the final result is hostname / literal IP address:port number.
For more information see the JavaDocs for InetSocketAddress's toString().
回答2:
Was able to find an example: http://discuss.itacumens.com/index.php?topic=46099.0
Basically it is correct :)
I'll need to debug elsewhere...
来源：https://stackoverflow.com/questions/10646857/what-does-java-inetsocketaddress-look-like-tostring