问题
I would like to use Scanner to scan any number of integer then get the average. Before I stop, I would like to type "END".
The code below has: Exception in thread "main" java.util.InputMismatchException error. That is because I scan a string rather than int type.
How should I solve this problem?
Thanks
public static int scanaverage()
{
System.out.println("Enter any number, type 'END' to exit");
Scanner input = new Scanner(System.in);
int total=0;
int count = 0;
while (!(input.nextLine().equals("END")))
{
total += input.nextInt();
count += 1;
}
return total / count;
}
回答1:
You could just scan the whole line and check if the line is a number like this
public static int scanaverage() {
System.out.println("Enter any number, type 'END' to exit");
Scanner input = new Scanner(System.in);
int total = 0;
int count = 0;
String line;
do {
line = input.nextLine();
try {
total += Integer.parseInt(line); // Cast the number, if it does not succeed catch the exception.
count += 1;
} catch(NumberFormatException e) {
if(!line.equalsIgnoreCase("end")) { // Wrong input
System.out.println("Wrong input, input another number or end");
}
}
} while (!line.equalsIgnoreCase("end"));
return total / count;
}
回答2:
The Exception is due to two read operation for getting one number, For Example take input as
1
2
3
END
Debug:
while loop condition input.nextLine()
will fetch 1
then input.nextInt()
will fetch 2
while loop condition input.nextLine()
will fetch 3
then input.nextInt()
will fetch END --> This will throw InputMismatchException
Hope the bellow code will work, except the part that Any non int input will break the loop
public static int scanaverage()
{
System.out.println("Enter any number, type 'END' to exit");
Scanner input = new Scanner(System.in);
int total=0;
int count = 0;
while (input.hasNextInt()))
{
total += input.nextInt();
count += 1;
}
return total / count;
}
回答3:
You can simply add a try catch block as follows.
public static int scanaverage()
{
System.out.println("Enter any number, type 'END' to exit");
Scanner input = new Scanner(System.in);
int total=0;
int count = 0;
while (!(input.nextLine().equals("END")))
{
try{
total += input.nextInt();
count += 1;
}catch(InputMismatchException e){
}
}
return total / count;
}
I haven't test it.
来源:https://stackoverflow.com/questions/33999566/how-to-type-a-string-to-end-a-integer-scanning-process-in-java