问题
I managed to enter the date 21-Feb-12017 (I know it's not a correct date) in Oracle 10g into a date column. Oracle accepted the date fine. When I tried to select it back in SQL Developer, SQL Developer displayed it as NULL. But when I tried to retrieve the date thru java, I got the value back as how I inserted. Wondering what's going on because I could also see that Oracle converted a different 5 digit year into a 4 digit year. I entered 21-Feb-21019 and Oracle converted the year to 4581 while storing. I could even select this value in SQL developer.
I was wondering if it be possible to read the original date back e.g 21-Feb-21019 changed to 21-Feb-4581, so how to read 21-Feb-21019 instead of 21-Feb-4581.
回答1:
Oracle stores DATE
s in tables using 7 bytes where the first 2 bytes are:
- Century + 100
- Year of century + 100
So the maximum date that can (technically) be stored is when those two bytes have the values 255
and 199
which would give the a year of 15599
(I'm ignoring that you could theoretically store 255
in the second byte as that opens up a whole heap of separate issues).
You can convert a raw value to a date using the DBMS_STATS.CONVERT_RAW_VALUE
which means we can bypass the normal methods of creating dates and directly generate the byte values which will be stored.
This function is an example of that:
CREATE FUNCTION createDate(
year int,
month int,
day int,
hour int,
minute int,
second int
) RETURN DATE DETERMINISTIC
IS
hex CHAR(14);
d DATE;
BEGIN
hex := TO_CHAR( FLOOR( year / 100 ) + 100, 'fm0X' )
|| TO_CHAR( MOD( year, 100 ) + 100, 'fm0X' )
|| TO_CHAR( month, 'fm0X' )
|| TO_CHAR( day, 'fm0X' )
|| TO_CHAR( hour + 1, 'fm0X' )
|| TO_CHAR( minute + 1, 'fm0X' )
|| TO_CHAR( second + 1, 'fm0X' );
DBMS_OUTPUT.PUT_LINE( hex );
DBMS_STATS.CONVERT_RAW_VALUE( HEXTORAW( hex ), d );
RETURN d;
END;
/
Then if you have a date column you can insert values you are not normally allowed to insert:
CREATE TABLE table_name ( date_column DATE );
INSERT INTO table_name ( date_column )
VALUES ( DATE '2019-12-31' + INTERVAL '1:02:03' HOUR TO SECOND );
INSERT INTO table_name ( date_column ) VALUES ( createDate( 15599, 12, 31, 1, 2, 3 ) );
INSERT INTO table_name ( date_column ) VALUES ( createDate( 12017, 2, 21, 0, 0, 0 ) );
TO_CHAR
does not work when the year exceeds the normal bounds of a date. To get the values stored in the table you can use DUMP
to get a string containing the byte values or you can use EXTRACT
to get the individual components.
SELECT DUMP( date_column ),
TO_CHAR( date_column, 'YYYY-MM-DD' ) AS value,
TO_CHAR( EXTRACT( YEAR FROM date_column ), 'fm00000' )
|| '-' || TO_CHAR( EXTRACT( MONTH FROM date_column ), 'fm00' )
|| '-' || TO_CHAR( EXTRACT( DAY FROM date_column ), 'fm00' )
|| ' ' || TO_CHAR( EXTRACT( HOUR FROM CAST( date_column AS TIMESTAMP ) ), 'fm00' )
|| ':' || TO_CHAR( EXTRACT( MINUTE FROM CAST( date_column AS TIMESTAMP ) ), 'fm00' )
|| ':' || TO_CHAR( EXTRACT( SECOND FROM CAST( date_column AS TIMESTAMP ) ), 'fm00' )
AS full_value
FROM table_name;
outputs:
DUMP(DATE_COLUMN) | VALUE | FULL_VALUE :-------------------------------- | :--------- | :------------------- Typ=12 Len=7: 120,119,12,31,2,3,4 | 2019-12-31 | 02019-12-31 01:02:03 Typ=12 Len=7: 255,199,12,31,2,3,4 | 0000-00-00 | 15599-12-31 01:02:03 Typ=12 Len=7: 220,117,2,21,1,1,1 | 0000-00-00 | 12017-02-21 00:00:00
db<>fiddle here
来源:https://stackoverflow.com/questions/59758473/oracle-10g-accepting-5-digit-year-in-a-date