问题
I was writing the code for non overlapping random circles with different radii.I kind of got the deserved, but my 'if' statement that checks overlap or non overlap excludes a number of circles. So, I get lesser number of circles. Here's the code:
import pygame
import numpy as np
pygame.init()
display_width = 800
display_height = 500
black = [0, 0, 0]
white = [255, 255, 255]
red = [255, 0, 0]
display_surface = pygame.display.set_mode((display_width, display_height))
clock = pygame.time.Clock()
pygame.display.set_caption("Random Circle")
def circle(x, y, r):
pygame.draw.circle(display_surface, red, (int(x), int(y)), int(r), 2)
def distance(x1, y1, x2, y2):
dsq = (x1 - x2) ** 2 + (y1 - y2) ** 2
d = np.sqrt(dsq)
return d
n = 100
r = np.random.randint(10, 20, size=n)
x = np.random.randint(r, display_width - r, size=n)
y = np.random.randint(r, display_height - r, size=n)
display_surface.fill(black)
for i in range(len(r)):
valid = True
for j in range(len(r)):
if i != j:
d = distance(x[i], y[i], x[j], y[j])
if d < r[i] + r[j]:
valid = False
if valid:
circle(x[i], y[i], r[i])
pygame.display.update()
clock.tick(100)
exit = False
while not exit:
for event in pygame.event.get():
if event.type == pygame.QUIT:
pygame.quit()
quit()
I saw an answer to a question here which does exactly what this code does( except it uses a class of circles which I didn't use). I sense that I have to use some kind of while loop which doesn't end until I get my desired number o circles. But I find difficulty in actually writing the code. Can anyone help?
回答1:
Create a list of circles Each circle is a tuple with 3 components, the x and y coordinate and the radius. Append new circles as long the length of the list is less than n:
circle_list = []
while len(circle_list) < n:
# [...]
Create a random position and radius:
r = random.randint(10, 20)
x = random.randint(r, display_width - r)
y = random.randint(r, display_height - r)
Evaluate if the circle intersects with a other circle wich is in the list:
collide = False
for x2, y2, r2 in circle_list:
d = distance(x, y, x2, y2)
if d < r + r2:
collide = True
break
Append the circle if it does not collide:
if not collide:
circle_list.append((x, y, r))
Minimal example:
import random
import math
import pygame
def euclidean_distance(x1, y1, x2, y2):
#return math.sqrt((x1 - x2) ** 2 + (y1 - y2) ** 2)
return math.hypot((x1 - x2), (y1 - y2))
pygame.init()
window = pygame.display.set_mode((400, 400))
font50 = pygame.font.SysFont(None, 50)
clock = pygame.time.Clock()
pygame.time.delay(10000)
run = True
circle_list = []
while run:
clock.tick(100)
for event in pygame.event.get():
if event.type == pygame.QUIT:
run = False
r = random.randint(10, 20)
x = random.randint(10+r, window.get_width()- r-10)
y = random.randint(10+r, window.get_height()-r-10)
if not any((x2, y2, r2) for x2, y2, r2 in circle_list if euclidean_distance(x, y, x2, y2) < r + r2):
circle_list.append((x, y, r))
window.fill((255, 255, 255))
for x, y, r in circle_list:
pygame.draw.circle(window, (0, 0, 0), (round(x), round(y)), int(r), 3)
window.blit(font50.render(str(len(circle_list)), True, (255, 0, 0)), (10, 10))
pygame.display.flip()
pygame.quit()
exit()
来源:https://stackoverflow.com/questions/62079192/random-non-overlapping-circleswith-circle-number-controlled-in-python-and-pyga