Form data to rest PUT method in java

问题

I am beginner for Java and REST API. I have a problem passing form data from HTML to rest PUT method. When I google about this, most solutions available are for POST method, that recommended to use FormParam. In my case, it shows below error:

The method received in the request-line is known by the origin server but not supported by the target resource.

Even I use PathParam, same error is returned:

The method received in the request-line is known by the origin server but not supported by the target resource.

And some solution for Spring Boot. But I did not use that.

PUT method:

@PUT
@Path("/update")
@Produces(MediaType.TEXT_HTML)
public String updCard(@PathParam("cardNo") String cardNo,  
        @PathParam("reportId") int reportId
        ) throws SQLException { 

    Card c = new Card(cardNo, reportId); 

    System.out.println(cardNo + reportId);
    
    return "";
}

Form:

 <form method="PUT" action="rest/card/update">
  <label for = "cardNo">Card No: </label> <input type="text" name = "cardNo" id = "cardNo"><br/>
  <label for = "reportId">Report Id:</label> <input type="text" name = "reportId" id = "reportId"> <br/>
  <button type="submit">Update</button>

So, how do I get the form data in PUT method in Jersey?

回答1:

As mentioned by many in Using PUT method in HTML form, PUT is not currently supported by the HTML standard. What most frameworks will do is offer a workaround. Jersey has such a workaround with its HttpMethodOverrideFilter. What you must do is use a POST method and add a _method=put query parameter and the filter will switch the POST to a PUT.

You first need to register the filter. If you are using a ResourceConfig just do

@ApplicationPath("api")
public class JerseyConfig extends ResourceConfig {

    public JerseyConfig() {
        ...
        register(HttpMethodOverrideFilter.class);
    }
}

If you are using a web.xml, then do

<init-param>
    <param-name>jersey.config.server.provider.classnames</param-name>
    <param-value>org.glassfish.jersey.server.filter.HttpMethodOverrideFilter</param-value>
</init-param>

Then in your HTML, you will just add the _method=put query param to the URL. Below is an example I used to test

<form method="post" action="/api/form?_method=put">
    <label>
        Name:
        <input type="text" name="name"/>
    </label>
    <label>
        Age:
        <input type="number" name="age"/>
    </label>
    <br/>
    <input type="submit" value="Submit"/>
</form>

And in your resource method you will use @PUT and @FormParams for the paramters

@PUT
@Consumes(MediaType.APPLICATION_FORM_URLENCODED)
public Response form(@FormParam("name") String name,
                     @FormParam("age") String age,
                     @Context UriInfo uriInfo) {

    URI redirectUri = UriBuilder
            .fromUri(getBaseUriWithoutApiRoot(uriInfo))
            .path("redirect.html")
            .queryParam("name", name)
            .queryParam("age", age)
            .build();
    return Response.temporaryRedirect(redirectUri).build();
}

private static URI getBaseUriWithoutApiRoot(UriInfo uriInfo) {
    String baseUri = uriInfo.getBaseUri().toASCIIString();
    baseUri = baseUri.endsWith("/")
            ? baseUri.substring(0, baseUri.length() - 1)
            : baseUri;
    return URI.create(baseUri.substring(0, baseUri.lastIndexOf("/")));
}

It should work from what I tested

来源：https://stackoverflow.com/questions/64263617/form-data-to-rest-put-method-in-java

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