问题
I have the following document structure
{
"_id" : ObjectId("5ffef283f1f06ff8524aa2c2"),
"applicationName" : "TestApp",
"pName" : "",
"environments" : [],
"stages" : [],
"createdAt" : ISODate("2021-01-15T09:51:35.546Z"),
"workflows" : [
[
{
"pName" : "Test1",
"wName" : "TestApp_Test1",
"agent" : ""
},
{
"pName" : "Test2",
"wName" : "TestApp_Test2",
"agent" : ""
}
],
[
{
"pName" : "Test1",
"wName" : "TestApp_Test1",
"agent" : ""
}
]
],
"updatedAt" : Date(-62135596800000)
}
I wish to remove the occurrences of
{
"pName" : "Test1",
"wName" : "TestApp_Test1",
"agent" : ""
}
So, the resultant document should look like
{
"_id" : ObjectId("5ffef283f1f06ff8524aa2c2"),
"applicationName" : "TestApp",
"pName" : "",
"environments" : [],
"stages" : [],
"createdAt" : ISODate("2021-01-15T09:51:35.546Z"),
"workflows" : [
[
{
"pName" : "Test2",
"wName" : "TestApp_Test2",
"agent" : ""
}
]
],
"updatedAt" : Date(-62135596800000)
}
I've tried the below mongo query
db.getCollection('workflows').update({_id:ObjectId('5ffef283f1f06ff8524aa2c2')}, {$pull:{workflows: { $elemMatch: {pipelineName: 'Test1'}}}} )
This is removing all the documents from workflows field including Test2 since Test1 is matched.
How can we remove only the entries for Test1 and keep the others ?
回答1:
You can do it using the positional operator "$[]" :
db.getCollection('workflows').update({_id: ObjectId("5ffef283f1f06ff8524aa2c2") }, {$pull: {"workflows.$[]":{pName:"Test1" } } } )
but the schema looks abit strange and after the update you will have empty arrays inside workflows if all elements got deleted in the sub-array. To fix the empty sub-arrays you will need to perform second operation to remove them:
db.getCollection('workflows').update({_id: ObjectId("5ffef283f1f06ff8524aa2c2") }, {$pull: {"workflows":[] } } )
回答2:
You cannot use $elemMatch
as it returns the first matching element in the array.
I am not sure there is another best way to do this with the provided schema design.
play
db.collection.aggregate({
"$unwind": "$workflows"
},
{
"$unwind": "$workflows"
},
{
"$match": {
"workflows.pName": {
"$ne": "Test1"
}
}
},
{
"$group": {
"_id": "$_id",
workflows: {
$push: "$workflows"
},
applicationName: {
"$first": "$applicationName"
}
}
},
{
"$group": {
"_id": "$_id",
workflows: {
$push: "$workflows"
},
applicationName: {
"$first": "$applicationName"
}
}
})
unwind
twice required to de-normalize the datamatch
to filter out the unnecessary docgroup
twice required to bring the required output
You can save this to a collection using $out
as last stage.
来源:https://stackoverflow.com/questions/65752420/how-to-remove-a-document-inside-an-array-in-mongodb-using-pull