Using FFT-Convolution when stride>1

二次信任 提交于 2021-01-29 05:11:47

问题


The Fourier transform of the convolution (with stride 1) of two images is equivalent to point-wise multiplication of their individual Fourier transforms. I need to perform stride-'n' convolution using the above FFT-based convolution. For some reasons I need to operate in the frequency domain itself after taking the point-wise product of the transforms, and not come back to space domain by taking inverse Fourier transform, so I cannot drop the excess values from the inverse Fourier transform output to get equivalent stride - 'n' convolution. How can I account for the stride in the frequency domain? Thanks.

来源:https://stackoverflow.com/questions/61246468/using-fft-convolution-when-stride1

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