问题
I want to concatenate two strings but in my output instead of getting the final concatenated string, I get a line of weird characters and spaces, maybe someone could help me a bit. I want to save the result in s3. Here is the code
DATA SEGMENT
STR1 DB "ENTER FIRST STRING HERE ->$"
STR2 DB "ENTER SECOND STRING HERE ->$"
STR3 DB "CONCATEnatedD STRING :->$"
STR11 DB "FIRST STRING : ->$"
STR22 DB "SECOND STRING: ->$"
s1 DB 20 DUP("$")
s2 DB 20 DUP("$")
s3 db 40 dup(?)
NEWLINE DB 10,13,"$"
DATA ENDS
CODE SEGMENT
ASSUME DS:DATA,CS:CODE
START:
MOV AX,DATA
MOV DS,AX
lea dx,str1
mov ah,09h
int 21h
lea si,s1
l1: mov ah,01h
int 21h
mov [si],al
inc si
cmp al,31h
jne l1
dec si
lea dx,str2
mov ah,09h
int 21h
lea di,s2
l2: mov ah,01h
int 21h
mov [di],al
inc di
cmp al,32h
jnz l2
lea si,s3
lea di,s1
lea si,s3
lea di,s1
l3: mov al,[di]
mov [si],al
inc si
inc di
cmp al,31h
jnz l3
dec si
lea di,s2
l4: mov al,[di]
mov [si],al
inc si
inc di
cmp al,32h
jnz l4
lea dx,str3
mov ah,09h
int 21h
l5: mov dl,[si]
cmp dl,32h
jz l6
mov ah,02h
int 21h
inc si
jmp l5
l6:MOV AH,4CH
INT 21H
CODE ENDS
END START
I have found the solution, hope it is a good one without any mistake: data segment msg db 0Dh, 0Ah, "String1: $" msg2 db 0Dh, 0Ah, "String2: $" rev db 0Dh, 0Ah, "Result: $"
buffer label byte
buffer2 label byte
str_maxlen db 255
str_length db 0
str_string db 255 dup(0)
str_string2 db 255 dup(0)
result db 255 dup('$')
num db 0
data ends
code segment
assume cs:code, ds:data
start:
mov ax,data
mov ds,ax
lea dx,msg
mov ah,09h
int 21h
lea dx,buffer
mov ah,0Ah
int 21h
mov cl,str_length
mov bh,cl
mov ch,0
lea si,str_string
lea di,result
op1: mov bl,[si]
mov [di],bl
inc di
inc si
loop op1
mov cl,bh
op3: dec si
loop op3
lea dx,msg2
mov ah,09h
int 21h
lea dx,buffer2
mov ah,0Ah
int 21h
mov cl,str_length
lea si,str_string
mov cl,str_length
mov ax,0
op2: mov al,[si]
mov [di],al
inc di
inc si
loop op2
lea dx,rev
mov ah,09h
int 21h
lea dx,result
mov ah,09h
int 21h
mov ah,4Ch
int 21h
code ends
end start
回答1:
In your first code, you have to set si
to point to the beginning of string s3
right before label l5:
(because si
was pointing to the end of s3
after loop l4:
) :
.
.
.
lea dx,str3
mov ah,09h
int 21h
lea si,s3 ;◄■■■■■■■■■■■
l5: mov dl,[si]
cmp dl,32h
jz l6
.
.
.
来源:https://stackoverflow.com/questions/38828212/assembly-concatenate-two-strings