Bash: Find position of character in a string under OS X

问题

Is there any way to find a position of a first character within a string in Bash under Mac OS X?

Something like:

stringZ=abcABC123ABCabc                      # 6
echo `expr index "$stringZ" C12`             # C position.

as desribed in Advanced Bash-Scripting Guide

Couple of gotchas:

1. The official index function expr index $string $substring is not present in OS X (BSD) match
2. Installing gnu match (gmatch) does not seem to be a portable solution in the realm of BSD systems

Any ideas?

回答1:

This is a horrible hack, and may not work for all cases.

tmp=${stringZ%%C12*}     # Remove the search string and everything after it
echo $(( ${#tmp} + 1 )) # Add one to the length of the remaining prefix

回答2:

Might be an overkill but how about this:

$ echo 'abcABC123ABCabc' | awk 'match($0,"C"){print RSTART}'
6

来源：https://stackoverflow.com/questions/17615750/bash-find-position-of-character-in-a-string-under-os-x