问题
So I have this custom register API which registers a user, but when user successfully register, I want it to have this message "You have successfully register an account!" But I tried a different method but get an error instead.
serializer.py
class UserCreate2Serializer(ModelSerializer):
email = EmailField(label='Email Address')
valid_time_formats = ['%H:%M', '%I:%M%p', '%I:%M %p']
birthTime = serializers.TimeField(format='%I:%M %p', input_formats=valid_time_formats, allow_null=True, required=False)
class Meta:
model = MyUser
fields = ['username', 'password', 'email', 'first_name', 'last_name', 'gender', 'nric', 'birthday', 'birthTime']
extra_kwargs = {"password": {"write_only": True}}
def validate(self, data): # to validate if the user have been used
email = data['email']
user_queryset = MyUser.objects.filter(email=email)
if user_queryset.exists():
raise ValidationError("This user has already registered.")
return data
def create(self, validated_data):
username = validated_data['username']
password = validated_data['password']
email = validated_data['email']
first_name = validated_data['first_name']
last_name = validated_data['last_name']
gender = validated_data['gender']
nric = validated_data['nric']
birthday = validated_data['birthday']
birthTime = validated_data['birthTime']
user_obj = MyUser(
username = username,
email = email,
first_name = first_name,
last_name = last_name,
gender = gender,
nric = nric,
birthday = birthday,
birthTime = birthTime,
)
user_obj.set_password(password)
user_obj.save()
return validated
views.py
class CreateUser2View(CreateAPIView):
permission_classes = [AllowAny]
serializer_class = UserCreate2Serializer
queryset = MyUser.objects.all()
I tried changing this into the serializer
user_obj.set_password(password)
user_obj.save()
content = {'Message': 'You have successfully register an account'}
return content
But got an error instead. I'm unsure how to do the custom response as I only know it is to be done on views.py
.
But if I do this on view:
class CreateUser2View(CreateAPIView):
permission_classes = [AllowAny]
serializer_class = UserCreate2Serializer
queryset = MyUser.objects.all()
def post(self, request):
content = {'Message': 'You have successfully register'}
return Response(content, status=status.HTTP_200_OK)
It will show this even if the validation is incorrect. Please help me as I'm still inexperienced in DRF.
回答1:
class CreateUser2View(CreateAPIView):
permission_classes = [AllowAny]
serializer_class = UserCreate2Serializer
queryset = MyUser.objects.all()
def create(self, request, *args, **kwargs):
serializer = self.get_serializer(data=request.data)
serializer.is_valid(raise_exception=True)
self.perform_create(serializer)
headers = self.get_success_headers(serializer.data)
return Response({'Message': 'You have successfully register'}, status=status.HTTP_201_CREATED, headers=headers)
来源:https://stackoverflow.com/questions/47975001/django-rest-framework-custom-return-response