conversion to inaccessible base class is not allowed [duplicate]

问题

This question already has answers here:

C++ inheritance - inaccessible base? (2 answers)

Closed 3 years ago.

I define a class B1 and a derived class D1 at first. Then I want to define a reference to B1 and initialize that to the D1 object I just defined. Here comes the error, saying that "conversion to inaccessible base class 'B1' is not allowed", which I don't know why.

#include "std_lib_facilities.h"

class B1 {
public:
    virtual void vf() { cout << "B1::vf()\n"; };
    void f() { cout << "B1::f()\n"; };
};

class D1 :B1 {
public:
    void vf() { cout << "D1:vf()\n"; };
    void f() { cout << "D1::f()\n"; };
};




int main()
{
    B1 b1;
    b1.vf();
    b1.f();

    D1 d1;
    d1.vf();
    d1.f();

    B1& db=d1;//error

    keep_window_open();
    return 0;
}

回答1:

class D1 :B1

Inheritance of classes is private by default, you should make it public:

class D1 : public B1

来源：https://stackoverflow.com/questions/47062562/conversion-to-inaccessible-base-class-is-not-allowed