How to define exception to be thrown through ref in Apache Camel

问题

Have to throw an exception in my camel route defined in XML. Found throwException statement available from Camel 2.3 which looks like:

 <throwException ref="forced"></throwException>

However, I don't know how to define forced exception class to be thrown. Since same exception could be thrown couple of times with different exception messages - would be good to know if throwException has some other form of definition so exception class and exception message are defined in-place.

回答1:

The ref is just a reference to a so you can do

<bean id="forced" class="java.lang.IllegalArgumentException">
   <constructor-arg index="0" value="This is forced"/>
</bean>

<camelContext ...>
  ...
</camelContext>

回答2:

Since version 2.16.0 there is more elegant way to do it, with optional exception message:

<route>
     <throwException exceptionType="java.lang.IllegalArgumentException" message="illegal argument found"/>
</route>

来源：https://stackoverflow.com/questions/5839612/how-to-define-exception-to-be-thrown-through-ref-in-apache-camel