What happens if I call a JS method with more parameters than it is defined to accept?

大城市里の小女人 提交于 2019-11-28 00:50:24

JavaScript doesn't have the concept of a fixed parameter list. For your own functions you can always specify as many parameters as you want and pass in as many as you want which ever type you want.

For built-in functions, which correlate to native code, it depends.

You asked on what it depends:

Let's look at the ECMA-262

Section 15 about built-in (not to confuse with host) functions in general

Unless otherwise specified in the description of a particular function, if a function or constructor described in this clause is given fewer arguments than the function is specified to require, the function or constructor shall behave exactly as if it had been given sufficient additional arguments, each such argument being the undefined value.

Alright. If I pass in less arguments than needed, it depends on the spec of the function itself (scroll down section 15 to find the spec for each built-in function).

Unless otherwise specified in the description of a particular function, if a function or constructor described in this clause is given more arguments than the function is specified to allow, the extra arguments are evaluated by the call and then ignored by the function. However, an implementation may define implementation specific behaviour relating to such arguments as long as the behaviour is not the throwing of a TypeError exception that is predicated simply on the presence of an extra argument.

Passing in too many arguments should never raise a TypeError. But still it may raise other errors. Again, it depends on the function you talk about.

You were talking explicitly about the DOM and not about built-in functions. To be honest I can't find the corresponding parts of the spec. The ECMA spec is so much easier to read then the w3 website.

Won't hurt. You can even call a function with less parameters than it takes, as long as the function code is ok with a few undefined values.

I don't think it will mess anything up unless you are explicitly dealing with the implicit arguments array. Why are you doing this though?

Chase

Try taking a look at this post and perhaps this one.

From MDN:

The arguments object is a local variable available within all functions; arguments as a property of Function can no longer be used.

You can refer to a function's arguments within the function by using the arguments object. This object contains an entry for each argument passed to the function, the first entry's index starting at 0.

You can use the arguments object if you call a function with more arguments than it is formally declared to accept. This technique is useful for functions that can be passed a variable number of arguments.

function myConcat(separator) {
  var result = "";

  // iterate through non-separator arguments
  for (var i = 1; i < arguments.length; i++) {
    result += arguments[i] + separator;
  }

  return result;
}

I came across this important, however old, question; and I hope it'll be beneficial for future generations to share my experiments with it:

  1. One can use the arguments object in order to access a function's arguments, regardless of the amount of arguments in the function's signature.
    It's worth mentioning that this doesn't apply to arrow functions:

// Results in an error, as 'arguments' isn't defined
((arg) => console.log(arguments))(1);
  1. It's stated in the documentation that arguments isn't exactly an Array:

    “Array-like” means that arguments has a length property and properties indexed from zero, but it doesn't have Array's built-in methods like forEach() and map().

    Hence the following code results in an error:

(function singleArg(x) {
  console.log(arguments); // This line works
  arguments.foreach(x => console.log(x)); // This causes an error
})(1, 2);
  1. Upon calling a function with less arguments than in its signature, they're assigned undefined:

(function twoArgs(a, b) {
  console.log(`a: ${a}\nb: ${b}`);
})(1);
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