问题
I am using spring-ldap-core plugin in my Sprint boot application. Basically, the LDAPTemplate - http://docs.spring.io/spring-ldap/docs/current/apidocs/org/springframework/ldap/core/LdapTemplate.html
I basically want to convert the xml configuration below into java using Spring LDAP API and want to avoid using spring security.
The xml configuration that I want to convert is -
<ldap-server id="ldapServer"
url="ldap://ad.company.com:389"
manager-dn="CN=serviceaccount,OU=Service Accounts,DC=ad,DC=company,DC=com"
manager-password="password"/>
<authentication-manager>
<ldap-authentication-provider
server-ref="ldapServer"
user-search-base="dc=ad,dc=company,dc=com"
user-search-filter="sAMAccountName={0}"
group-search-filter="member={0}"
group-search-base="ou=Groups,dc=ad,dc=company,dc=com"
group-role-attribute="cn"/>
</authentication-manager>
Here is my java code below-
import org.springframework.context.annotation.Bean;
import org.springframework.context.annotation.Configuration;
import org.springframework.ldap.core.LdapTemplate;
import org.springframework.ldap.core.support.LdapContextSource;
import org.springframework.ldap.authentication.DefaultValuesAuthenticationSourceDecorator;
@Configuration
public class LdapConfiguration {
@Bean
public LdapContextSource contextSource(){
LdapContextSource contextSource = new LdapContextSource();
contextSource.setUrl("ldap://ad.company.com:389");
contextSource.setBase("DC=ad,DC=company,DC=com");
contextSource.setUserDn("CN=serviceaccount,OU=Service Accounts,DC=ad,DC=company,DC=com");
contextSource.setPassword("password");
contextSource.afterPropertiesSet();
return contextSource;
}
@Bean
public LdapTemplate ldapTemplate(){
LdapTemplate template = new LdapTemplate(contextSource());
try {
template.afterPropertiesSet();
} catch (Exception e) {
e.printStackTrace();
}
return template;
}
}
This is how I am trying to invoke authentication - The method that this snippet is a part of returns a boolean value if authentication happens
AndFilter filter = new AndFilter();
filter.and(new EqualsFilter("sAMAccountName", userloginName));
return ldapTemplate.authenticate("OU=Service Accounts", filter.encode(), userPassword);
This is not working and the error I get is that :
No results found for search, base: 'OU=Service Accounts'; filter: '(sAMAccountName=usernameIinput)'.
I want to know how the following xml properties can be configured using LDAP API?
group-search-filter="member={0}"
group-search-base="ou=Groups,dc=ad,dc=company,dc=com"
group-role-attribute="cn"/>
Also, what else am I missing? Why is this not working? Any help will be really appreciated!
回答1:
I was able to figure this out.
//LDAP connection using LDAPTemplate
@Configuration
public class LdapConfiguration {
@Bean
public LdapContextSource contextSource(){
LdapContextSource contextSource = new LdapContextSource();
contextSource.setUrl("ldap://companyurl.com:389");
contextSource.setUserDn("CN=serviceaccount,OU=Service Accounts,DC=ad,DC=company,DC=com");
contextSource.setPassword("secretpassword");
return contextSource;
}
@Bean
public LdapTemplate ldapTemplate(){
LdapTemplate template = new LdapTemplate(contextSource());
return template;
}
}
//Authentication portion
AndFilter filter = new AndFilter();
filter.and(new EqualsFilter("mailNickname", username));
Boolean authenticate = ldapTemplate.authenticate(base, filter.encode(), userpassword);
来源:https://stackoverflow.com/questions/40180421/authenticating-using-ldap-with-spring-ldap-api-and-without-using-spring-security