问题
Firstly, apologies for how obvious these two questions seem to be; I'm very very new to this and don't have a clue what I'm doing.
I'm trying to write something to apply the Scipy function for spline interpolation to an array of values. My code currently looks like this:
import numpy as np
import scipy as sp
from scipy.interpolate import interp1d
x=var
x1 = ([0.1,0.3,0.4])
y1 = [0.2,0.5,0.6]
new_length = 25
new_x = np.linspace(x.min(), x.max(), new_length)
new_y = sp.interpolate.interp1d(x, y, kind='cubic')(new_x)
but when it gets to the line
new_x = np.linspace(x.min(), x.max(), new_length)
I get the following error:
AttributeError: 'function' object has no attribute 'min'
and so far googling etc has turned up nothing that I understand. What does this mean and how do I fix it?
Second question: how do I input more than one line of code at once? At the moment, if I try to copy the whole thing and then paste it into PyLab, it only inputs the top line of my code, so I have to paste the whole thing in one line at a time. How do I get round this?
回答1:
If this line
new_x = np.linspace(x.min(), x.max(), new_length)
is generating the error message
AttributeError: 'function' object has no attribute 'min'
then x
is a function, and functions (in general) don't have min
attributes, so you can't call some_function.min()
. What is x
? In your code, you've only defined it as
x=var
I'm not sure what var
is. var
isn't a default builtin in Python, but if it's a function, then either you've defined it yourself for some reason or you've picked it up from somewhere (say you're using Sage, or you did a star import like from sympy import *
or something.)
[Update: since you say you're "using PyLab", probably var
is numpy.var
which has been imported into scope at startup in IPython. I think you really mean "using IPython in --pylab
mode.]
You also define x1
and y1
, but then your later code refers to x
and y
, so it sort of feels like this code is halfway between two functional states.
Now numpy
arrays do have a .min()
and .max()
method, so this:
>>> x = np.array([0.1, 0.3, 0.4, 0.7])
>>> y = np.array([0.2, 0.5, 0.6, 0.9])
>>> new_length = 25
>>> new_x = np.linspace(x.min(), x.max(), new_length)
>>> new_y = sp.interpolate.interp1d(x, y, kind='cubic')(new_x)
would work. Your test data won't because the interpolation needs at least 4 points, and you'd get
ValueError: x and y arrays must have at least 4 entries
回答2:
Second question: how do I input more than one line of code at once? At the moment, if I try to copy the whole thing and then paste it into PyLab, it only inputs the top line of my code, so I have to paste the whole thing in one line at a time. How do I get round this?
Assuming you're in ipython
called as ipython --pylab
or something similar, then you can simply use the paste magic command. Call it as %paste
or simply paste
if you haven't defined paste
as another variable:
In [8]: paste
import numpy as np
import scipy as sp
from scipy.interpolate import interp1d
x=var
x1 = ([0.1,0.3,0.4])
y1 = [0.2,0.5,0.6]
new_length = 25
new_x = np.linspace(x.min(), x.max(), new_length)
new_y = sp.interpolate.interp1d(x, y, kind='cubic')(new_x)
## -- End pasted text --
---------------------------------------------------------------------------
NameError Traceback (most recent call last)
<ipython-input-8-b4e41f59d719> in <module>()
3 from scipy.interpolate import interp1d
4
----> 5 x=var
6 x1 = ([0.1,0.3,0.4])
7 y1 = [0.2,0.5,0.6]
NameError: name 'var' is not defined
In [9]:
回答3:
Change that line to:
new_x = np.linspace(min(x), max(x), new_length)
min
and max
are not attributes of lists, they are their own functions.
回答4:
I encountered a similar error when I called timezone.now
instead of timezone.now()
. I then tried to format the DateTime
value that I was expecting. But it wasn't a DateTime
; it was a function. This resulted in an error message about 'Month' not being an attribute of 'function'.
The fix was to simply add the parentheses after now
. This called the now
function and returned its result, instead of returning the now function
object itself.
Silly mistake, I know. But not easy to troubleshoot.
回答5:
I got the similar issue.
My error was I named a variable and function name as same.
I corrected that and error vanished.
回答6:
Int's don't have a min() function but min() is a builtin function. You'll need to use min(x).
来源:https://stackoverflow.com/questions/15930454/python-attributeerror-function-object-has-no-attribute-min