Full precision display of floating point numbers in C++?

问题

I have read several topics about the display of floating point numbers display in C++ and I couldn't find a satisfying answer.

My question is: how to display all the significant digits of a floating point numbers in C++ in a scientific format (mantissa/exponent) ?

The problem is that all numbers do not have the same number of significant digits in base 10.

For example a double has 15 to 17 significant decimal digits precision, but std::numeric_limits<double>::digits10 returns 15 and consequently, for some numbers I will loose 2 extra decimal digits of precision.

回答1:

The value std::numeric_limits<double>::digits10 provides the number of decimal digits which can safely be restored, i.e., the number of decimal digits which survive a round-trip decimal->double->decimal. Assuming more decimal digits are correct isn't helpful. If you want to faciliate the round-trip double->decimal->double you'd use std::numeric_limits<double>::max_digits10.

If you want the exact values you'd use std::numeric_limits<double>::digits but it will display numbers converted from decimal values in a funny way as they are normally rounded values. This is also the reason why max_digits10 isn't useful when presenting numbers for human consumption: the last couple of digits are normally not those expect by the human reader.

回答2:

Have you looked at std::max_digits10?

From cppreference:

The value of std::numeric_limits<T>::max_digits10 is the number of base-10 digits that are necessary to uniquely represent all distinct values of the type T, such as necessary for serialization/deserialization to text. This constant is meaningful for all floating-point types.

The implication of this (and is how I use it) is that the text output can be copy/pasted into another program and the number will represent the same number.

Now, I must say that my work-horse format is always right-justified %23.16E, and I use engineering judgement for the last few digits. I like it because is is sufficient for the sign, the exponent, and sixteen digits.

-----------------------
-1.1234567812345678E+12

Now, notice that digits of precision and decimal digits of precision are not necessarily the same thing.

回答3:

In C++20 you'll be able to use std::format to do this:

std::cout << std::format("{}", M_PI);

Output (assuming IEEE754 double):

3.141592653589793

The default floating-point format is the shortest decimal representation with a round-trip guarantee. The advantage of this method compared to using the precision of max_digits10 from std::numeric_limits is that it doesn't print unnecessary digits. For example:

std::cout << std::setprecision(
  std::numeric_limits<double>::max_digits10) << 0.3;

prints 0.29999999999999999 while

std::cout << std::format("{}", 0.3);

prints 0.3 (godbolt).

In the meantime you can use the {fmt} library, std::format is based on. {fmt} also provides the print function that makes this even easier and more efficient (godbolt):

fmt::print("{}", M_PI);

Disclaimer: I'm the author of {fmt} and C++20 std::format.

来源：https://stackoverflow.com/questions/19610161/full-precision-display-of-floating-point-numbers-in-c