问题

Given a map such as this where we have a frequency count per day-of-week for a year:

Map.of(
    DayOfWeek.MONDAY , 52 ,
    DayOfWeek.TUESDAY , 52 ,
    DayOfWeek.WEDNESDAY, 53 ,
    DayOfWeek.THURSDAY , 53 ,
    DayOfWeek.FRIDAY , 52 ,
    DayOfWeek.SATURDAY , 52 ,
    DayOfWeek.SUNDAY , 52 
)

…or as text:

{MONDAY=52, TUESDAY=52, WEDNESDAY=53, THURSDAY=53, FRIDAY=52, SATURDAY=52, SUNDAY=52}

…how can I invert to produce a multimap of distinct numbers each leading to a collection (list? set?) of the DayOfWeek which owned that number?

The result should be equivalent to the result of this code:

Map.of(
    53 , List.of( DayOfWeek.WEDNESDAY , DayOfWeek.THURSDAY ) ,
    52 , List.of( DayOfWeek.MONDAY , DayOfWeek.TUESDAY , DayOfWeek.FRIDAY , DayOfWeek.SATURDAY , DayOfWeek.SUNDAY ) 
)

I would like to produce the resulting multimap using straight Java without extra libraries such as Eclipse Collections or Google Guava. Those libraries might make this easier, but I am curious to see if a solution using only built-in Java is possible. Otherwise, my Question here is the exact same Question as Guava: construct a Multimap by inverting a Map. Given new streams and multimap features in modern Java, I expect this is possible now while it was not then.

I saw various existing Questions similar to this. But none fit my situation, which seems like a rather common situation. For example, this Question neglects the issue of the original values being redundant/multiple, thus necessitating a multimap as a result. Others such as this or this involve Google Guava.

回答1:

The following works using Java 9 or above:

@Test
void invertMap()
{
    Map<DayOfWeek, Integer> map = Map.of(
            DayOfWeek.MONDAY, 52,
            DayOfWeek.TUESDAY, 52,
            DayOfWeek.WEDNESDAY, 53,
            DayOfWeek.THURSDAY, 53,
            DayOfWeek.FRIDAY, 52,
            DayOfWeek.SATURDAY, 52,
            DayOfWeek.SUNDAY, 52
    );

    Map<Integer, Set<DayOfWeek>> flipped = new TreeMap<>();
    map.forEach((dow, count) ->
            flipped.computeIfAbsent(count, (key) ->
                    EnumSet.noneOf(DayOfWeek.class)).add(dow));

    Map<Integer, Set<DayOfWeek>> flippedStream = map.entrySet().stream()
           .collect(Collectors.groupingBy(
                    Map.Entry::getValue, 
                    TreeMap::new,
                    Collectors.mapping(
                            Map.Entry::getKey,
                            Collectors.toCollection(
                                    () -> EnumSet.noneOf(DayOfWeek.class)))));

    Map<Integer, Set<DayOfWeek>> expected = Map.of(
            53, EnumSet.of(
                    DayOfWeek.WEDNESDAY, 
                    DayOfWeek.THURSDAY),
            52, EnumSet.of(
                    DayOfWeek.MONDAY, 
                    DayOfWeek.TUESDAY, 
                    DayOfWeek.FRIDAY, 
                    DayOfWeek.SATURDAY, 
                    DayOfWeek.SUNDAY)
    );
    Assert.assertEquals(expected, flipped);
    Assert.assertEquals(expected, flippedStream);
}

If you are open to using a third-party library, the following code will work with Eclipse Collections:

@Test
void invertEclipseCollectionsMap()
{
    MutableMap<DayOfWeek, Integer> map =
            Maps.mutable.<DayOfWeek, Integer>empty()
                    .withKeyValue(DayOfWeek.MONDAY, 52)
                    .withKeyValue(DayOfWeek.TUESDAY, 52)
                    .withKeyValue(DayOfWeek.WEDNESDAY, 53)
                    .withKeyValue(DayOfWeek.THURSDAY, 53)
                    .withKeyValue(DayOfWeek.FRIDAY, 52)
                    .withKeyValue(DayOfWeek.SATURDAY, 52)
                    .withKeyValue(DayOfWeek.SUNDAY, 52);

    SetMultimap<Integer, DayOfWeek> flipped = map.flip();

    Assert.assertEquals(flipped.get(52), Set.of(
            DayOfWeek.MONDAY,
            DayOfWeek.TUESDAY,
            DayOfWeek.FRIDAY,
            DayOfWeek.SATURDAY,
            DayOfWeek.SUNDAY));
    Assert.assertEquals(flipped.get(53), Set.of(
            DayOfWeek.WEDNESDAY,
            DayOfWeek.THURSDAY));
}

Note: I am a committer for Eclipse Collections.

回答2:

`Collectors.toMap`

In this case you can use method Collectors.toMap(keyMapper,valueMapper,mergeFunction) and produce multimap where the value can be a list or a set:

Multimap value is a List:

Map<Integer, List<DayOfWeek>> inverted = map.entrySet().stream()
        .collect(Collectors.toMap(
                // key of the new map
                entry -> entry.getValue(),
                // value of the new map
                entry -> List.of(entry.getKey()),
                // merging two values, i.e. lists
                (list1, list2) -> {
                    List<DayOfWeek> list = new ArrayList<>();
                    list.addAll(list1);
                    list.addAll(list2);
                    return list;
                }));

Multimap value is a Set:

Map<Integer, Set<DayOfWeek>> inverted = map.entrySet().stream()
        .collect(Collectors.toMap(
                // key of the new map
                entry -> entry.getValue(),
                // value of the new map
                entry -> Set.of(entry.getKey()),
                // merging two values, i.e. sets
                (set1, set2) -> {
                    Set<DayOfWeek> set = new HashSet<>();
                    set.addAll(set1);
                    set.addAll(set2);
                    return set;
                }));

^{See also: Collect a list of ids based on multiple fields}

回答3:

With streams, you can split a map into its entries, then flip the entries and group:

numberOfDaysInYear.entrySet().stream()
  .collect(groupingBy(Map.Entry::getValue), mapping(Map.Entry::getKey, toList()));

Based on your updated comments asking for optimization not actually in your original question,

numberOfDaysInYear.entrySet().stream()
  .collect(groupingBy(
    Map.Entry::getValue,
    TreeMap::new,
    mapping(Map.Entry::getKey, toCollection(() -> EnumSet.of(DayOfWeek.class)))
  ));

回答4:

Please refer below code:

@Test
void testMap() {
    Map<DayOfWeek, Integer> map = new HashMap<>();
    map.put(DayOfWeek.MONDAY, 52);
    map.put(DayOfWeek.TUESDAY, 52);
    map.put(DayOfWeek.WEDNESDAY, 53);
    map.put(DayOfWeek.THURSDAY, 53);
    map.put(DayOfWeek.FRIDAY, 52);
    map.put(DayOfWeek.SATURDAY, 52);
    map.put(DayOfWeek.SUNDAY, 52);

    Map<Integer, List<DayOfWeek>> result = new HashMap<>();

    for (Map.Entry<DayOfWeek, Integer> entry : map.entrySet()) {
        if (result.containsKey(entry.getValue())) {
            List list = result.get(entry.getValue());
            list.add(entry.getKey());
            result.put(entry.getValue(), list);
        } else {
            List list = new ArrayList();
            list.add(entry.getKey());
            result.put(entry.getValue(), list);
        }
    }
    System.out.println(result);
}

来源：https://stackoverflow.com/questions/65473915/invert-a-map-with-redundant-values-to-produce-a-multimap

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