问题
I have a json object that looks like this (prodused by i3-msg -t get_workspaces.
[
{
"name": "1",
"urgent": false
},
{
"name": "2",
"urgent": false
},
{
"name": "something",
"urgent": false
}
]
I am trying to use jq to figure out which index number in the list is based on a select query. jq have something called index(), but it seams to support only strings?
Using something like i3-msg -t get_workspaces | jq '.[] | select(.name=="something")' gives me the object I want. But I want it's index. In this case 2 (starting counting at 0)
Is this possible using jq alone?
回答1:
So I provided a strategy for a solution to the OP, which OP quickly accepted. Subsequently @peak and @Jeff Mercado offered better and more complete solutions. So I have turned this into a community wiki. Please improve this answer if you can.
A straightforward solution (pointed out by @peak) is to use the builtin function, index:
map(.name == "something") | index(true)
The jq documentation confusingly suggests that index operates on strings, but it operates on arrays as well. Thus index(true) returns the index of the first true in the array of booleans produced by the map. If there is no item satisfying the condition, the result is null.
jq expresions are evaluated in a "lazy" manner, but map will traverse the entire input array. We can verify this by rewriting the above code and introducing some debug statements:
[ .[] | debug | .name == "something" ] | index(true)
As suggested by @peak, the key to doing better is to use the break statement introduced in jq 1.5:
label $out |
foreach .[] as $item (
-1;
.+1;
if $item.name == "something" then
.,
break $out
else
empty
end
) // null
Note that the // is no comment; it is the alternative operator. If the name is not found the foreach will return empty which will be converted to null by the alternative operator.
Another approach is to recursively process the array:
def get_index(name):
name as $name |
if (. == []) then
null
elif (.[0].name == $name) then
0
else
(.[1:] | get_index($name)) as $result |
if ($result == null) then null else $result+1 end
end;
get_index("something")
However this recursive implementation will use stack space proportional to the length of the array in the worst case as pointed out by @Jeff Mercado. In version 1.5 jq introduced Tail Call Optimization (TCO) which will allow us to optimize this away using a local helper function (note that this is minor adaptation to a solution provided by @Jeff Mercado so as to be consistent with the above examples):
def get_index(name):
name as $name |
def _get_index:
if (.i >= .len) then
null
elif (.array[.i].name == $name) then
.i
else
.i += 1 | _get_index
end;
{ array: ., i: 0, len: length } | _get_index;
get_index("something")
According to @peak obtaining the length of an array in jq is a constant time operation, and apparently indexing an array is inexpensive as well. I will try to find a citation for this.
Now let's try to actually measure. Here is an example of measuring the simple solution:
#!/bin/bash
jq -n '
def get_index(name):
name as $name |
map(.name == $name) | index(true)
;
def gen_input(n):
n as $n |
if ($n == 0) then
[]
else
gen_input($n-1) + [ { "name": $n, "urgent":false } ]
end
;
2000 as $n |
gen_input($n) as $i |
[(0 | while (.<$n; [ ($i | get_index(.)), .+1 ][1]))][$n-1]
'
When I run this on my machine, I get the following:
$ time ./simple
1999
real 0m10.024s
user 0m10.023s
sys 0m0.008s
If I replace this with the "fast" version of get_index:
def get_index(name):
name as $name |
label $out |
foreach .[] as $item (
-1;
.+1;
if $item.name == $name then
.,
break $out
else
empty
end
) // null;
Then I get:
$ time ./fast
1999
real 0m13.165s
user 0m13.173s
sys 0m0.000s
And if I replace it with the "fast" recursive version:
def get_index(name):
name as $name |
def _get_index:
if (.i >= .len) then
null
elif (.array[.i].name == $name) then
.i
else
.i += 1 | _get_index
end;
{ array: ., i: 0, len: length } | _get_index;
I get:
$ time ./fast-recursive
1999
real 0m52.628s
user 0m52.657s
sys 0m0.005s
Ouch! But we can do better. @peak mentioned an undocumented switch --debug-dump-disasm which lets you see how jq is compiling your code. With this you can see that modifying and passing the object to _indexof and then extracting the array, length, and index is expensive. Refactoring to just pass the index is a huge improvement, and a further refinement to avoid testing the index against the length makes it competitive with the iterative version:
def indexof($name):
(.+[{name: $name}]) as $a | # add a "sentinel"
length as $l | # note length sees original array
def _indexof:
if ($a[.].name == $name) then
if (. != $l) then . else null end
else
.+1 | _indexof
end
;
0 | _indexof
;
I get:
$ time ./fast-recursive2
null
real 0m13.238s
user 0m13.243s
sys 0m0.005s
So it appears that if each element is equally likely, and you want an average case performance, you should stick with the simple implementation. (C-coded functions tend to be fast!)
回答2:
The solution originally proposed by @Jim-D using foreach would only work as intended for arrays of JSON objects, and both the originally proposed solutions are very inefficient. Their behavior in the absence of an item satisfying the condition might also have been surprising.
Solution using index/1
If you just want a quick-and-easy solution, you can use the builtin function, index, as follows:
map(.name == "something") | index(true)
If there is no item satisfying the condition, then the result will be null.
Incidentally, if you wanted ALL indices for which the condition is true, then the above is easily transformed into a super-fast solution by simply changing index to indices:
map(.name == "something") | indices(true)
Efficient solution
Here is a generic and efficient function that returns the index (i.e. offset) of the first occurrence of the item in the input array for which (item|f) is truthy (neither null nor false), and null otherwise. (In jq, javascript, and many others, the index into arrays is always 0-based.)
# 0-based index of item in input array such that f is truthy, else null
def which(f):
label $out
| foreach .[] as $x (-1; .+1; if ($x|f) then ., break $out else empty end)
// null ;
Example usage:
which(.name == "something")
回答3:
Converting an array to entries will give you access to both the index and value in the array of the items. You could use that to then find the value you're looking for and get its index.
def indexof(predicate):
reduce to_entries[] as $i (null;
if (. == null) and ($i.value | predicate) then
$i.key
else
.
end
);
indexof(.name == "something")
This however does not short circuit and will go through the entire array to find the index. You'll want to return as soon as the first index has been found. Taking a more functional approach might be more appropriate.
def indexof(predicate):
def _indexof:
if .i >= .len then
null
elif (.arr[.i] | predicate) then
.i
else
.i += 1 | _indexof
end;
{ arr: ., i: 0, len: length } | _indexof;
indexof(.name == "something")
Note that the arguments are passed in to the inner function in this way to take advantage of some optimizations. Namely to take advantage of TCO, the function must not accept any additional parameters.
A still faster version can be obtained by recognizing that the array and its length do not vary:
def indexof(predicate):
. as $in
| length as $len
| def _indexof:
if . >= $len then null
elif ($in[.] | predicate) then .
else . + 1 | _indexof
end;
0 | _indexof;
来源：https://stackoverflow.com/questions/41958475/getting-the-object-array-index-in-jq