问题
I have snake that is turning and drawing trajectory behind him but I don't know how to make holes like random pauses while he's drawing. I tried it and it's not random but problem is that it's very fast pause. It's like teleporting move. Here is my code:
import pygame
pygame.init()
import random
from random import randint
win = pygame.display.set_mode((1280,720))
background = pygame.Surface(win.get_size(), pygame.SRCALPHA)
background.fill((0, 0, 0, 1))
x = randint(150,1130)
y = randint(150,570)
vel = 0.6
drawing_time = 0
direction = pygame.math.Vector2(vel, 0).rotate(random.randint(0, 360))
run = True
while run:
pygame.time.delay(5)
drawing_time += 1
if drawing_time == 1000:
for pause in range(0, 60):
head = pygame.draw.circle(win, (255,0,0), (round(x), round(y)), 0)
keys = pygame.key.get_pressed()
if keys[pygame.K_LEFT]:
direction.rotate_ip(-0.8)
if keys[pygame.K_RIGHT]:
direction.rotate_ip(0.8)
x += direction.x
y += direction.y
time = 0
keys = pygame.key.get_pressed()
if keys[pygame.K_LEFT]:
direction.rotate_ip(-0.8)
if keys[pygame.K_RIGHT]:
direction.rotate_ip(0.8)
x += direction.x
y += direction.y
win.blit(background, (12020,0))
head= pygame.draw.circle(win, (255,0,0), (round(x), round(y)), 5)
pygame.display.update()
pygame.quit()
I tried to give that head radius 0 and maybe that is problem but I don't have any idea how to solve it.
回答1:
Never implement a loop that controls the game in the application loop. You need application loop. Use it!
Use pygame.time.get_ticks() to return the number of milliseconds since pygame.init() was called. Add a variable that indicates whether or not the snake needs to be drawn (draw_snake). Define a variable that indicates the time when the status needs to be changed (next_change_time ). When the time has expired, change the status of the variable and define a new random time at which the status must be changed again. Only draw the snake when the variable is set. this causes holes in the snake:
next_change_time = 0
draw_snake = False
run = True
while run:
# [...]
current_time = pygame.time.get_ticks()
if current_time > next_change_time:
next_change_time = current_time + random.randint(500, 1000)
draw_snake = not draw_snake
# [...]
if draw_snake:
pygame.draw.circle(win, (255,0,0), (round(x), round(y)), 5)
# [...]
Use pygame.time.Clock to control the frames per second and thus the game speed.
The method tick() of a pygame.time.Clock object, delays the game in that way, that every iteration of the loop consumes the same period of time.
That means that the loop:
clock = pygame.time.Clock() run = True while run: clock.tick(60)
runs 60 times per second.
Complete example:
import pygame
pygame.init()
import random
from random import randint
win = pygame.display.set_mode((1280,720))
background = pygame.Surface(win.get_size(), pygame.SRCALPHA)
background.fill((0, 0, 0, 1))
clock = pygame.time.Clock()
x = randint(150,1130)
y = randint(150,570)
vel = 0.6
drawing_time = 0
next_change_time = 0
draw_snake = False
direction = pygame.math.Vector2(vel, 0).rotate(random.randint(0, 360))
run = True
while run:
clock.tick(60)
for event in pygame.event.get():
if event.type == pygame.QUIT:
run = False
current_time = pygame.time.get_ticks()
if current_time > next_change_time:
next_change_time = current_time + random.randint(500, 1000)
draw_snake = not draw_snake
keys = pygame.key.get_pressed()
if keys[pygame.K_LEFT]:
direction.rotate_ip(-0.8)
if keys[pygame.K_RIGHT]:
direction.rotate_ip(0.8)
x += direction.x
y += direction.y
win.blit(background, (12020,0))
if draw_snake:
pygame.draw.circle(win, (255,0,0), (round(x), round(y)), 5)
pygame.display.update()
pygame.quit()
If you want other size for the holes you need, additional condition and different random time:
if current_time > next_change_time:
draw_snake = not draw_snake
if draw_snake:
next_change_time = current_time + random.randint(500, 1000)
else:
next_change_time = current_time + random.randint(250, 500)
来源：https://stackoverflow.com/questions/65363717/how-can-i-randomly-make-holes-in-snake