问题
I need to close a popup window from the website itself by pressing the "X" window on the top right. Here is the shortened, relevant part of my code:
chromedriver = r'C:\Users\do\Desktop\chromedriver.exe'
browser = webdriver.Chrome(chromedriver)
url = 'Fake.com'
browser.get(url)
browser.find_element_by_id('imgAttachmentsImg').click()
# I need to close out the window after this
The issue is that there are no unique identifiers for the "X" button itself. However, the pop up itself does have a unique identifier. I just need to be able to flow it down to the X button.
Info from the page:
1. V<div class="ui-dialog ui-widget ui-widget-content ui-corner-all ui-front ui-draggable ui-resizable" tabindex="-1" role="dialog" aria-describedby="attachmentsDialogOverview" aria-labelledby="ui-id-3" style="position: absolute; height: auto; width: auto; top: 239px; left: 102px; display: block;">
2. <div class="ui-dialog-titlebar ui-widget-header ui-corner-all ui-helper-clearfix">
3. <span id="ui-id-3" class="ui-dialog-title">Attachments</span>
4. V<button type="button" class="ui-button ui-widget ui-state-default ui-corner-all ui-button-icon-only ui-dialog-titlebar-close" role="button" aria-disabled="false" title="close">
5. <span class="ui-button-icon-primary ui-icon ui-icon-closethick"</span>
6. <span class="ui-button-text">close</span></button>
I am new to using Python and Selenium. I switched over from VBA and still don't exactly understand all the syntax yet, so I do make mistakes! I did find a bandaid solution by just having sendkeys press Escape. But I am trying to actually understand how to actually solve this. I am not sure what errors I made with my solution:
browser.find_element_by_xpath("//span[@id, 'ui-id-3']/following-sibling::button").click()
Questions
Why did my solution not work?
How would I locate "ui-id-3"(on line 3) and get to the element on Line 4 to click it?
How would I locate "ui-id-3"(on line 3) and get to the element on Line 5 to click it? (just so I know how to move across multiple elements)
Relevant links I looked over:
Following-Sibling Python Selenium
Find next sibling element in Python Selenium?
Using XPath Selector 'following-sibling::text()' in Selenium (Python)
Python + Selenium WebDriver - Get div value if sibling contains string
What is the correct syntax for using a variable and following-sibling in Python Selenium?
回答1:
The xpath has a problem. this should work:
browser.find_element_by_xpath("//span[@id='ui-id-3']/following-sibling::button").click()
To get to the span below it, you could use:
browser.find_element_by_xpath("//span[@id='ui-id-3']/following-sibling::button/span")
by the way, if you're more comfortable with CSS, the equivalent paths would be:
div#ui-id-3 > button
div#ui-id-3 > button span:nth-of-type(1)
来源：https://stackoverflow.com/questions/49054985/python-selenium-getting-the-element-after-an-element