Sort based on Frequency in R

问题

Structure of input dataframe

ds= structure(list(MSISDN = c(800, 800, 783, 
975, 800)), .Names = "Number", row.names = c(NA, 
-5L), class = "data.frame")

Need a simple output which looks like below (not able to add single break)

Num Freq

800 3

975 1

783 1

回答1:

Check out Tabyl function from janitor package. It does the task that you want plus a bit more

library(janitor)
    ds <- structure(list(MSISDN = c(800, 800, 783,975, 800)), .Names = "Number", row.names = c(NA,-5L), class = "data.frame")

    tabyl(ds$Number)

回答2:

This should work.

Base

df <- data.frame(table(xx$Number))
df[rev(order(df$Freq)),]

Result

  #    Var1 Freq
  #    800    3
  #    975    1
  #    783    1

You can sort using dplyr as well.

library(dplyr)
df %>% arrange(desc(Freq))

Data

xx <- structure(list(MSISDN = c(800, 800, 783, 
975, 800)), .Names = "Number", row.names = c(NA, 
-5L), class = "data.frame")

回答3:

using only dplyr

xx %>% group_by(Number) %>% summarise(Freq=n()) %>% arrange(desc(Freq))

来源：https://stackoverflow.com/questions/49883606/sort-based-on-frequency-in-r