问题
I am pretty new to Angular and I was wondering if there is any way to increment the ngFor loop by 2 instead of 1.
I am trying to implement two pagination's with in a pagination for which increment the loop by 2 is required.
I am getting objects which have objects with in. Lets say users and list of their address.
(First NgFor is to paginate the users by 2. If I get 15 users. 2 users will be displayed in one page)
li *ngFor="let user of Users | paginate: { itemsPerPage: 1, currentPage: p };let i = index"
{{user[i].firstName}} <--Displaying first userName-->
(Second NgFor is to display list of address of the first user. Lets say he has 20 address. I will be slicing it to 3 or 4 per page and paginate the rest)
*ngFor="let address of user[i].address| objectValues |slice:addresspageNumber*2-2:addressPageNumber*5 ; let j = index "
<--First child Pagination code-->
{{user[i+1].firstName}} <--Displaying second userName-->
(Third NgFor is to display list of address of the second user. Lets say he has 20 address. I will be slicing it to 3 or 4 per page and paginate the rest)
*ngFor="let address of user[i+1].address| objectValues |slice:addresspageNumber*2-2:addressPageNumber*5 ; let j = index ">
<th scope="row">{{address.streetno}}
<--Second child Pagination code-->
<--Parent Pagination code-->
Now if I dont increment the first ngFor by two, in the next page the second user will be displayed again which I dont want to.
I either have to increment by 2 or implement pagination seperately for two childs which I cant do it in one for loop
All I want is two separate pagination's to be implemented with in one pagination
Object1.name object1.address.street object1.address.pin -- pagination to display other address.
Object2.name object2.address.street object2.address.pin -- second pagination to display other address. --main pagination which on click will show two more object details
回答1:
I don't think you can increment *ngFor
by 2 because it's purpose is to display an array-kind data; plus I don't really understand your requirements.
However you can use *ngIf
in a combination with %
operator in order to not react on every second entry.
This could do the job
<li *ngFor="let item of items; let i = index">
<span *ngIf="i % 2 === 0"> // or <ng-template if it is better here>
The same effect could be achieved for any iteration size. Just replace the 2
with e.g. 10
to increment by 10.
回答2:
For increment by 2
<div *ngFor="let item of items; let even = even;">
<div *ngIf="even">
// content
</div>
来源:https://stackoverflow.com/questions/45176953/angular-2-increment-ngfor-by-2-or-implementing-two-paginations-with-in-a-pagi