问题
I have 2 tables: restaurants and foods, and a 3rd table restaurants_foods which stores the many to many relationship between the 2 tables
restaurants_foods = db.Table('restaurants_foods',
db.Column('restaurant_id', db.Integer, db.ForeignKey('restaurants.id'), primary_key=True),
db.Column('food_id', db.Integer, db.ForeignKey('foods.id'), primary_key=True),
db.Column('food_price', db.Float)
)
class Food(Model):
__tablename__ = "foods"
id = db.Column(db.Integer, primary_key=True, autoincrement=True)
name = db.Column(db.String(255), nullable=False)
description = db.Column(db.String(255), nullable=True)
class Restaurant(Model):
__tablename__ = "restaurants"
id = db.Column(db.Integer, primary_key=True, autoincrement=True)
name = db.Column(db.String(255), nullable=False)
foods = db.relationship('Food', secondary=restaurants_foods)
Now when i query Restautant.query.get(1).foods, I want it to include the food_price column from the restaurants_foods association table
回答1:
You have to use an association object pattern (is a variant of definition on many-to-many): it’s used when your association table contains additional columns beyond those which are foreign keys to the left and right tables. Instead of using the relationship.secondary argument, you map a new class directly to the association table. The left side of the relationship references the association object via one-to-many, and the association class references the right side via many-to-one. Below illustrate an association table mapped to the Association class which includes a column called extra_data, which is a string value that is stored along with each association between Parent and Child:
class Association(Base):
__tablename__ = 'association'
left_id = Column(Integer, ForeignKey('left.id'), primary_key=True)
right_id = Column(Integer, ForeignKey('right.id'), primary_key=True)
extra_data = Column(String(50))
child = relationship("Child", back_populates="parents")
parent = relationship("Parent", back_populates="children")
class Parent(Base):
__tablename__ = 'left'
id = Column(Integer, primary_key=True)
children = relationship("Association", back_populates="parent")
class Child(Base):
__tablename__ = 'right'
id = Column(Integer, primary_key=True)
parents = relationship("Association", back_populates="child")
回答2:
Please take a look at configuring many-to-many relationships in SQLAlchemy. You're going to want something like this:
restaurants_foods = db.Table('restaurants_foods',
db.Column('restaurant_id', db.Integer, db.ForeignKey('restaurants.id'), primary_key=True),
db.Column('food_id', db.Integer, db.ForeignKey('foods.id'), primary_key=True),
db.Column('food_price', db.Float))
class Food(Model):
__tablename__ = "foods"
id = db.Column(db.Integer, primary_key=True, autoincrement=True)
name = db.Column(db.String(255), nullable=False)
description = db.Column(db.String(255), nullable=True)
restaurants = relationship(
"Restaurant",
secondary=restaurant_foods,
back_populates="foods"
)
class Restaurant(Model):
__tablename__ = "restaurants"
id = db.Column(db.Integer, primary_key=True, autoincrement=True)
name = db.Column(db.String(255), nullable=False)
foods = relationship(
"Food",
secondary=restaurant_foods,
back_populates="restaurants"
)
来源:https://stackoverflow.com/questions/35795717/flask-sqlalchemy-many-to-many-relationship-with-extra-field