问题
I want to create a notification without canceling/deleting previous notifications from my app. Here is my code for creating a notification:
private void notification(Context context, String title, String content) {
NotificationCompat.Builder mBuilder =
new NotificationCompat.Builder(context)
.setSmallIcon(R.drawable.notification_icon)
.setContentTitle(title)
.setContentText(content);
Intent resultIntent = new Intent(context, MainActivity.class);
TaskStackBuilder stackBuilder = TaskStackBuilder.create(context);
// Adds the back stack for the Intent (but not the Intent itself)
stackBuilder.addParentStack(MainActivity.class);
// Adds the Intent that starts the Activity to the top of the stack
stackBuilder.addNextIntent(resultIntent);
PendingIntent resultPendingIntent =
stackBuilder.getPendingIntent(
0,
PendingIntent.FLAG_UPDATE_CURRENT
);
mBuilder.setContentIntent(resultPendingIntent);
NotificationManager mNotificationManager =
(NotificationManager) context.getSystemService(Context.NOTIFICATION_SERVICE);
//Id allows you to update the notification later on.
mNotificationManager.notify(100, mBuilder.build());
}
回答1:
You are using a hardcoded id for your notification, of course it will replace the old one. Try using a variable ID instead of a hardcoded 100.
mNotificationManager.notify(100+x, mBuilder.build());
or something of the sort.
回答2:
Use variable id for notification, I have faced this issue 1 Hour ago And used this technique to overcome this issue.
val id= Random(System.currentTimeMillis()).nextInt(1000)
mNotificationManager?.notify(id, mBuilder.build())
回答3:
for long term solutions, you can use a random method to generate integer variable for you and call that in notify.
mNotificationManager.notify(createRandomCode(7), mBuilder.build());
public int createRandomCode(int codeLength) {
char[] chars = "1234567890".toCharArray();
StringBuilder sb = new StringBuilder();
Random random = new SecureRandom();
for (int i = 0; i < codeLength; i++) {
char c = chars[random.nextInt(chars.length)];
sb.append(c);
}
return Integer.parseInt(sb.toString());
}
来源:https://stackoverflow.com/questions/24439236/android-after-creating-a-new-notification-the-older-one-is-replaced