python parallel assignment of 3 variables

问题

My question is from a popular coding test.

Given a chain defined as follows:

class ListNode:
     def __init__(self, x):
         self.val = x
         self.next = None

If we want to revert the chain, for example:

Input:1->2->3->4->5->NULL

Output: 5->4->3->2->1->NULL

It can be solved like this:

class Solution:
    def reverseList(self, head: ListNode) -> ListNode:
        cur, pre = head, None
        while cur:
            tmp = cur.next 
            cur.next = pre 
            pre = cur      
            cur = tmp     
        return pre

But there is a more compact way, which I can't really follow:

class Solution:
    def reverseList(self, head: ListNode) -> ListNode:
        cur, pre = head, None
        while cur:
            cur.next, pre, cur = pre, cur, cur.next
        return pre

Because if I change the parallel assignment line to

            pre, cur, cur.next = cur, cur.next, pre

It wouldn't work properly anymore.

I am wondering how does the parallel assignment of python works, especially in the case that all 3 variables are dynamic.

回答1:

When you write a parallel assignment

x, y, z = a, b, c

it's equivalent to

temp = (a, b, c)
x = temp[0]
y = temp[1]
z = temp[2]

So in the failing version, it's equivalent to

temp = (cur, cur.next, pre)
pre = temp[0]
cur = temp[1]
cur.next = temp[2]

Compare this to the working version:

cur.next = temp[0]
pre = temp[1]
cur = temp[2]

The difference is that in your version, you assign to cur.next after you've stepped cur to cur.next, so you're actually assigning to the original cur.next.next.

来源：https://stackoverflow.com/questions/65085517/python-parallel-assignment-of-3-variables

标签

python

python-3.x

variable-assignment