问题
I have two VMs (VirtualBOx, Ubuntu 18.04 and python-zmq[16.0.2-2build2]) running within the same physical machine (Win10). Both machines are configured as Bridge and they can be ping successfully 192.168.1.66-192.168.1.55. I've followed this tutorial https://learning-0mq-with-pyzmq.readthedocs.io/en/latest/pyzmq/patterns/pubsub.html. It works if PUB (server) is configured as
import zmq
import random
import sys
import time
port = "5557"
if len(sys.argv) > 1:
port = sys.argv[1]
int(port)
context = zmq.Context()
socket = context.socket(zmq.PUB)
socket.bind("tcp://*:%s" % port)
while True:
topic = random.randrange(9999,10005)
messagedata = random.randrange(1,215) - 80
print "%d %d" % (topic, messagedata)
socket.send("%d %d" % (topic, messagedata))
time.sleep(1)
And the SUB (client) as
import sys
import zmq
port = "5557"
if len(sys.argv) > 1:
port = sys.argv[1]
int(port)
if len(sys.argv) > 2:
port1 = sys.argv[2]
int(port1)
# Socket to talk to server
context = zmq.Context()
socket = context.socket(zmq.SUB)
print "Collecting updates from weather server..."
socket.connect ("tcp://192.168.1.66:%s" % port)
if len(sys.argv) > 2:
socket.connect ("tcp://localhost:%s" % port1)
# Subscribe to zipcode, default is NYC, 10001
topicfilter = "10001"
socket.setsockopt(zmq.SUBSCRIBE, topicfilter)
# Process 5 updates
total_value = 0
for update_nbr in range (5):
string = socket.recv()
topic, messagedata = string.split()
total_value += int(messagedata)
print topic, messagedata
print "Average messagedata value for topic '%s' was %dF" % (topicfilter, total_value / update_nbr)
Since I want a single client (SUB) with multiple servers (PUB) where they can be hundreds even thousands, it is unfeasible to configure a single IP for each PUB. Is there a way to subscribe without specifying the IP? Or at least a broadcast one. I've tried to configure at client in socket.connect ("tcp://IP:%s" % port)
:
"*"
Gives the error:
Traceback (most recent call last):
File "sub_client.py", line 18, in <module>
socket.connect ("tcp://*:%s" % port)
File "zmq/backend/cython/socket.pyx", line 528, in zmq.backend.cython.socket.Socket.connect (zmq/backend/cython/socket.c:5980)
File "zmq/backend/cython/checkrc.pxd", line 25, in zmq.backend.cython.checkrc._check_rc (zmq/backend/cython/socket.c:8400)
zmq.error.ZMQError: Invalid argument
192.168.1.1 (GW), 192.168.1.255 (broadcast), localhost/127.0.0.1 and it's IP (192.168.1.55) -> does not receive messages
192.168.1.66 (server's IP) -> Does receive messages but not practical in a large scale system
Any way to solve this?
回答1:
Q : Any way to solve this?
Avoid going against any API-documented property. While a .bind()
-method can for the tcp://
-transport-class try to indeed bind to any localhost
-side IP-addresses, the .connect()
-method, for obvious reasons can't.
As was notified in the ZMQError
:
socket.connect ("tcp://*:%s" % port)
zmq.error.ZMQError: Invalid argument
Correct the IP-address target, where shall the.connect( "tcp://{0:}:{1:}".format( IP, PORT ) )
-method try to "ring-so-as-to-get-connection".
来源:https://stackoverflow.com/questions/64918425/how-configure-a-multiple-pub-single-sub-python-zmq-ubuntu