问题
import scala.reflect.runtime.universe
import scala.reflect.runtime.universe._
def getType[T: TypeTag](obj: T) = typeOf[T]
case class Thing(
val id: Int,
var name: String
)
val thing = Thing(1, "Apple")
val dataType = getType(thing).decl(TermName("id")).asTerm.typeSignature
dataType match {
case t if t =:= typeOf[Int] => println("I am Int")
case t if t =:= typeOf[String] => println("String, Do some stuff")
case _ => println("Absurd")
}
Not able to digest why result is Absurd
instead of I am int
?
My aim is to know data-type of class parameter at runtime and match it to predefined types.
回答1:
Both current dataType
and typeOf[Int]
are printed as Int
but if you do showRaw
you'll see why they don't match
showRaw(dataType) // NullaryMethodType(TypeRef(ThisType(scala), scala.Int, List()))
showRaw(typeOf[Int]) // TypeRef(ThisType(scala), scala.Int, List())
The thing is that just the type Int
and the type of nullary method returning Int
are different types.
Try to add .resultType
val dataType = getType(thing).decl(TermName("id")).asTerm.typeSignature.resultType
dataType match {
case t if t =:= typeOf[Int] => println("I am Int")
case t if t =:= typeOf[String] => println("String, Do some stuff")
case _ => println("Absurd")
} // I am Int
It's also worth mentioning that .decl(TermName("id"))
returns getter symbol, it's .decl(TermName("id "))
(with a blank space) that returns field symbol. So alternatively you can do with a blank space in the symbol name and without .resultType
val dataType = getType(thing).decl(TermName("id ")).asTerm.typeSignature
I'll add to @TomerShetah's answer that if the goal is "pattern matching" all fields of a case class then this can be done also at compile time (mostly) with Shapeless:
import shapeless.Poly1
import shapeless.syntax.std.product._
object printTypes extends Poly1 {
implicit val int: Case.Aux[Int, Unit] = at(t => println(s"I am Int: $t"))
implicit val string: Case.Aux[String, Unit] = at(t => println(s"String, Do some stuff: $t"))
implicit def default[V]: Case.Aux[V, Unit] = at(t => println(s"Absurd: $t"))
}
thing.toHList.map(printTypes)
// I am Int: 1
// String, Do some stuff: Apple
https://scastie.scala-lang.org/DmytroMitin/N4Idk4KcRumQJZE2CHC0yQ
回答2:
@Dmytrio answer is a great explanation why the reflection didn't work as you expected.
I can understand from your question, that what you are trying to do, is actually pattern match all variables you have in a case class. Please consider doing it in the following way:
case class Thing(id: Int, name: String)
val thing = Thing(1, "Apple")
thing.productIterator.foreach {
case t: Int => println(s"I am Int: $t")
case t: String => println(s"String, Do some stuff: $t")
case t => println(s"Absurd: $t")
}
Code run at Scastie.
来源:https://stackoverflow.com/questions/65062245/how-to-find-class-parameter-datatype-at-runtime-in-scala