问题
I want to pass list values in IN clause using jdbcTemplate in mysql query. Like below,
List<Long> listId= new ArrayList<>();
listId.add(1234L);
listId.add(1235L);
listId.add(1236L);
String type ="A";
List<BojoClass> result = new ArrayList<>();
String sql="select column1,column2 from table where columName in(?)"
result = jdbcTemplate.query(sql, new Object[]{listId}, new BeanPropertyRowMapper<BojoClass>(BojoClass.class));
How to achieve this in best way?
回答1:
NamedParameterJdbcTemplate
may help for you.
For your sample, try this please:)
NamedParameterJdbcTemplate jdbcTemplate = ...
List<Long> listId= new ArrayList<>();
listId.add(1234L);
listId.add(1235L);
listId.add(1236L);
String sql="select column1,column2 from table where columName in(:ids)";
List<BojoClass> result = new ArrayList<>();
Map idsMap = Collections.singletonMap("ids", listId);
result = jdbcTemplate.query(sql, idsMap, ParameterizedBeanPropertyRowMapper.newInstance(BojoClass.class));
Edited:
If you can get DataSource
, you can just init a NamedParameterJdbcTemplate
object by its constructor like:
NamedParameterJdbcTemplate namedParameterJdbcTemplate = new NamedParameterJdbcTemplate(jdbcTemplate.getDataSource());
回答2:
You can join your list with StringUtils.join(paramListForInClause, ",");
to generate the string you need
来源:https://stackoverflow.com/questions/37518094/how-to-pass-list-parameter-in-in-clause-using-jdbctemplate