问题
I want to use Laravel 5.1 Collection's Unique method to filter unique IDs from nested objects.
Given the data structure
{
"key1": [
{"id": 1},
{"id": 1}
],
"key2": [
{"id": 1},
{"id": 2}
]
}
I want to return the same datastructure with duplicate id 1
removed from "key 1".
I wanted to use $unique = $collection->unique('id');
, but this doesn't seem to apply to a nested datastructure as I have.
So I thought to use $collection
$input = $request->all();
$collection = collect($input);
$collection->each(function($obj, $key) {
//$key is "key1", "key2"
//obj is the associated array of objects containing IDs
})->unique('id');
I don't quite know how to structure this.
The result structure should be:
{
"key1": [
{"id": 1}
],
"key2": [
{"id": 1},
{"id": 2}
]
}
回答1:
$collection = $collection->map(function ($array) {
return collect($array)->unique('id')->all();
});
回答2:
if you have numeric List then you can use this code
$dataList = [1,2,4,5,3,2,1,98,1,2,4,5,6];
$dataList = collect( $dataList )->unique();
you will get all the unique list.
[1,2,4,5,3,98,6]
来源:https://stackoverflow.com/questions/33571628/laravel-collection-get-unique-values-from-nested-datastructure