In Django admin, how to filter users by group?

问题

It gives you filter by staff status and superuser status, but what about groups?

回答1:

Since version 1.3 it can be done using this:

list_filter = ('groups__name')

Of course as @S.Lott explains you must register your customized class in the admin.py file:

from django.contrib import admin
from django.contrib.auth.admin import UserAdmin
from django.contrib.auth.models import User

class MyUserAdmin(UserAdmin):
    list_filter = UserAdmin.list_filter + ('groups__name',)

admin.site.unregister(User)
admin.site.register(User, MyUserAdmin)

回答2:

See Customizing an Admin form in Django while also using autodiscover

Essentially, you define a customized Admin class with the features you want.

Then unregister and register your revised Admin class.

admin.site.unregister(User)
admin.site.register(User, MyUserAdmin)

回答3:

Here is a complete example, that inherits from SimpleListFilter, which is available in Django 1.4 and up.

https://docs.djangoproject.com/en/1.4/ref/contrib/admin/#django.contrib.admin.ModelAdmin.list_filter

It support setting all available labels and parameters to create the completely custom filter.

It shows up as "By group" in the filter panel, with a list of all available groups.

from django.contrib.admin import SimpleListFilter
from django.contrib.auth.models import Group
from django.utils.translation import ugettext as _

class GroupListFilter(SimpleListFilter):
    title = _('group')
    parameter_name = 'group'

    def lookups(self, request, model_admin):
        items = ()
        for group in Group.objects.all():
            items += ((str(group.id), str(group.name),),)
        return items

    def queryset(self, request, queryset):
        group_id = request.GET.get(self.parameter_name, None)
        if group_id:
            return queryset.filter(groups=group_id)
        return queryset

from django.contrib import admin
from django.contrib.auth.admin import UserAdmin
from django.contrib.auth.models import User

class MyUserAdmin(UserAdmin):
    list_filter = UserAdmin.list_filter + (GroupListFilter,)

admin.site.unregister(User)
admin.site.register(User, MyUserAdmin)

回答4:

In later versions of Django, it works exactly as you'd expect:

list_filter = ('groups', )

No need to unregister/register the admin class.

来源：https://stackoverflow.com/questions/880684/in-django-admin-how-to-filter-users-by-group

标签

django

django-admin

django-authentication