问题
It occurred to me that in C++ it is possible to use the type std::optional<std::reference_wrapper<T>>
. An object of this type is essentially a reference to an object of type T
or a null value, i.e., pretty much a pointer. My questions:
Is there any conceptual difference between
std::optional<std::reference_wrapper<T>>
andT*
?Is there any practical difference? Are there situations where it might be advisable to choose
std::optional<std::reference_wrapper<T>>
overT*
?
回答1:
Is there any conceptual difference between
std::optional<std::reference_wrapper<T>>
andT*
?
std::optional<>
, as the name already suggest, is meant to be used when we could have a value or might not have any value at all.
The equivalent of having no value for a T*
object would be assigning nullptr
to it, i.e.: the pointer will point to nowhere, as opposed to somewhere (or even anywhere, i.e.: uninitialized). It can be said that std::optional<>
exports the concept of nullptr
for pointers to any arbitrary type. So, I would say they are conceptually very similar, being the std::option<>
approach a kind of generalization.
Is there any practical difference? Are there situations where it might be advisable to choose
std::optional<std::reference_wrapper<T>>
overT*
?
I can think of the size. std::optional<>
contains an internal flag for indicating the presence/absence of a value, whereas for T*
the nullptr
is encoded directly as one of the values the pointer can store. So a std::optional<std::reference_wrapper<T>>
object will be larger than a T*
.
When it comes to safety, unlike T*
, std::optional<>
provides the member function value()
which throws an exception if there is no value (it provides as well as the unsafe operator*()
as T*
does).
Also, using std::optional<std::reference_wrapper<T>>
instead of T*
, for example, as a function's return value may indicate in a more explicit way that there might be no value at all.
回答2:
The main difference between std::optional<std::reference_wrapper<T>>
and T*
is that with T*
you have to think about who owns the memory that is pointed to.
If a function returns T*
you have to know if you are responsible for freeing the memory or someone else is. That's not something you have to be concerned with when it's a reference.
来源:https://stackoverflow.com/questions/48721313/does-it-make-sense-to-combine-optional-with-reference-wrapper