问题
I am trying to loop an array using a recursive function. The loop should stop and return the value of the key, if it matches a given regex pattern.
The loop stops correctly when the condition is met. However, it only returns the key's value if the match occurs for the first key (index 0) in the array and returns 'undefined' for the rest.
Where's my mistake? Here's the code to better illustrate:
function loop(arr,i) {
var i = i||0;
if (/i/gim.test(arr[i])){
console.log("key value is now: " + arr[i])
return arr[i]; // return key value
}
// test key value
console.log("key value: " + arr[i]);
// update index
i+=1;
// recall with updated index
loop(arr,i);
}
console.log( loop(["I","am", "lost"]) );
// "key value is now: I"
// "I" <-- the returned value
console.log( loop(["am", "I", "lost"]) );
// "key value: am"
// "key value is now: I" <-- test log
// undefined <-- but the return value is undefined! why?!
回答1:
You have to return
the value from the recursive call,
// recall with updated index
return loop(arr,i);
}
The final call for the function loop
will return a value, but the other calls for the same function returns undefined
. So finally you end up in getting undefined
来源:https://stackoverflow.com/questions/36069423/javascript-recursive-function-returns-undefined-for-existing-value